Determine the acceleration and position of the bullet

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SUMMARY

The discussion focuses on determining the acceleration and position of a bullet as it travels down a rifle barrel, using the velocity equation v = (-4.80 × 107) t2 + (2.45 × 105) t. The acceleration function derived is a(t) = -9.6 × 107 t + 2.45 × 105. The position function, calculated as the integral of velocity, is given as s(t) = -16,000,000 t3 + 122,500 t2. The user initially struggled with significant figures, which led to errors in their calculations.

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Homework Statement





The speed of a bullet as it travels down the barrel of a rifle toward the opening is given by v = (-4.80 107) t 2 + (2.45 105) t, where v is in meters per second and t is in seconds. The acceleration of the bullet just as it leaves the barrel is zero.
(a) Determine the acceleration and position of the bullet as a function of time when the bullet is in the barrel. (Use t as necessary and round all numerical coefficients to exactly 3 significant figures.)



The Attempt at a Solution




acceleration = -9.6*10^7t + 2.45 * 10^5

position of bullet with as a function of time = -16000000t^3 + 122500t^2



I am getting the second one wrong and I do not know why. Displacement is the integral of velocity but it keeps saying I am wrong. I have tried using scientific notation, and a variety of other things, but always get it wrong.
 
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nvm I got it. I didn't use significant figures
 

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