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Determine the acceleration and position of the bullet

  1. Sep 30, 2009 #1
    1. The problem statement, all variables and given/known data



    The speed of a bullet as it travels down the barrel of a rifle toward the opening is given by v = (-4.80 107) t 2 + (2.45 105) t, where v is in meters per second and t is in seconds. The acceleration of the bullet just as it leaves the barrel is zero.
    (a) Determine the acceleration and position of the bullet as a function of time when the bullet is in the barrel. (Use t as necessary and round all numerical coefficients to exactly 3 significant figures.)



    3. The attempt at a solution


    acceleration = -9.6*10^7t + 2.45 * 10^5

    position of bullet with as a function of time = -16000000t^3 + 122500t^2



    I am getting the second one wrong and I do not know why. Displacement is the integral of velocity but it keeps saying I am wrong. I have tried using scientific notation, and a variety of other things, but always get it wrong.
     
  2. jcsd
  3. Sep 30, 2009 #2
    Re: kinematics

    nvm I got it. I didn't use significant figures
     
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