Determine the acceleration of a rocket.

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SUMMARY

The discussion focuses on determining the acceleration of a rocket during its ascent phase, which lasts 30 seconds, and calculating its maximum altitude. The key equations used include kinematic equations such as x = x0 + v0t + 1/2 at² and v = v0 + at. The calculated acceleration required for the rocket to achieve the desired flight time of 300 seconds is approximately 406.71 m/s², taking into account the effects of gravity during the free-fall phase. The participants clarify the distinction between the two phases of motion: powered ascent and free fall.

PREREQUISITES
  • Understanding of kinematic equations in physics
  • Knowledge of gravitational acceleration (g = 9.81 m/s²)
  • Familiarity with concepts of projectile motion
  • Ability to solve algebraic equations involving multiple variables
NEXT STEPS
  • Study the derivation of kinematic equations for vertical motion
  • Learn how to analyze motion in two phases: powered ascent and free fall
  • Explore the effects of varying acceleration on projectile trajectories
  • Investigate real-world applications of rocket propulsion and flight dynamics
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Students studying physics, aerospace engineers, and anyone interested in the principles of rocket motion and dynamics.

  • #31
oh my bad then
i thought for calculation purposes only they wanted u to assume tohe rocket fell aft fuel ran out
thanks for clearing up the free fall term for me
 
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  • #32
roovid said:
oh my bad then
i thought for calculation purposes only they wanted u to assume tohe rocket fell aft fuel ran out
thanks for clearing up the free fall term for me

How can a rocket change its velocity to zero in no time, without fuel? :biggrin: Even the problem maker can not assume nonsense...

ehild
 
  • #33
lol i kno
but some of the question i am doing are makin me assume some weird stuff
for basic calculation purposes
sorry.my error
thnx fr the correction again
 
  • #34
You are welcome. :smile:

ehild
 
  • #35
So a = 176 ms^2?
 
  • #36
Squizzel said:
So a = 176 ms^2?

No. How did you get it?

ehild
 
  • #37
Nm I did a calculation error. I now did 0 = 450a + 30a(270) - 1/2 (9.81)(270)^2 = 70 ms-2
 
  • #38
How can be 0=70 m/s2? Solve the equation for a.

ehild
 
  • #39
I didn't do the long work in that message, but that's what it came out to I brought the 1/2 x 9.81 x 270 squared to the other side and then divded by 450 + 30 x 270
 
  • #40
Squizzel said:
I didn't do the long work in that message, but that's what it came out to I brought the 1/2 x 9.81 x 270 squared to the other side and then divded by 450 + 30 x 270

That is not 70. 1/2 x 9.81 x 2702 =357574.5
450 + 30 x 270=8550

357574.5/8550=?

ehild
 

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