- #1

Northbysouth

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## Homework Statement

Collars A and B slide along the fixed right-angle rods and are connected by a cord of length L = 7 m. Determine the acceleration of collar B when y = 2.2 m if collar A is given a constant upward velocity v

_{A}= 2.66 m/s. The acceleration of B is positive if to the right, negative if to the left.

I have attached an image

## Homework Equations

x

^{2}+y

^{2}= l

^{2}

**3. The Attempt at a Solution [/b**

I found the distance x, from the base of the support to B to be 6.64529 m

I took the derivative of the Pythagorean to get:

2xx' + 2yy' = 0

Then I took the derivative again:

2x'x' + 2xx" + 2y'

Solving for x" = -x'

x" = -(-yy'/x)

x" = -0.9057

But it says it's wrong. Where is my mistake?

I found the distance x, from the base of the support to B to be 6.64529 m

I took the derivative of the Pythagorean to get:

2xx' + 2yy' = 0

Then I took the derivative again:

2x'x' + 2xx" + 2y'

^{2}+ 2yy"Solving for x" = -x'

^{2}- y'^{2}-yy"/xx" = -(-yy'/x)

^{2}- y'^{2}/xx" = -0.9057

But it says it's wrong. Where is my mistake?