Collars A and B slide along the fixed right-angle rods and are connected by a cord of length L = 7 m. Determine the acceleration of collar B when y = 2.2 m if collar A is given a constant upward velocity vA = 2.66 m/s. The acceleration of B is positive if to the right, negative if to the left.
I have attached an image
x2+y2 = l2
3. The Attempt at a Solution [/b
I found the distance x, from the base of the support to B to be 6.64529 m
I took the derivative of the Pythagorean to get:
2xx' + 2yy' = 0
Then I took the derivative again:
2x'x' + 2xx" + 2y'2 + 2yy"
Solving for x" = -x'2 - y'2 -yy"/x
x" = -(-yy'/x)2 - y'2/x
x" = -0.9057
But it says it's wrong. Where is my mistake?
20 KB Views: 1,361