1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Determine the Acceleration of the plate for which there is no Force

  1. Apr 20, 2013 #1
    1. The problem statement, all variables and given/known data
    The right-angle bar with equal legs weighs 6.0 lb and is freely hinged to the vertical plate at C. The bar is prevented from rotating by the two pegs A and B fixed to the plate. Determine the acceleration a of the plate for which no force is exerted on the bar by A either B peg or .

    I have attached an image of the question

    2. Relevant equations



    3. The attempt at a solution

    I'm pretty sure this is a striaghtforward question but I think I'm missing something.

    First I summed the forces in the x and y direction.

    ƩFy = may = Cy - mg

    Cy = mg

    ƩFx = max = Cx

    Then I took the moment about the origin. I assigned the origin as being inbetween A and B.

    And I found the center to be (2,6)

    ƩM = -1/6*mg -8/12*Cx + 8/12*Cy

    Cx = 3/4*mg

    ax = a = Cx/m = [(3/4)mg]/m = (3/4)g

    But the answer should be 3g. Where am I making my mistake?

    Any help would be appreciated.
     

    Attached Files:

  2. jcsd
  3. Apr 20, 2013 #2
    I looked over the question again and this time I took the moment at the center of mass (2,6)

    Hence:

    ƩMG = 0 = -2/12*Cx + 6/12*Cy

    Cx = 3mg

    a = Cx/m = 3mg/m = 3g

    So, I've got the right answer, but why didn't it work when I took the moment about the Origin I assigned? What is the significance of taking the moment about the center of the shape?
     
  4. Apr 20, 2013 #3

    PhanthomJay

    User Avatar
    Science Advisor
    Homework Helper
    Gold Member

    Acceleration of a system is always acceleration of the center of mass of the system. Since your force Cx is at the hinge and not at the center of mass, you must choose the center of mass as your rotation point when summing moments. Or use the concept of the pseudo force "-ma" applied at the center of mass, then you can sum moments equal 0 about any point.
     
  5. Apr 30, 2014 #4
    how did you find the center to be at (2, 6)?
     
  6. Apr 30, 2014 #5

    haruspex

    User Avatar
    Science Advisor
    Homework Helper
    Gold Member
    2016 Award

    I agree with that location. Are you asking because you disagree or because you really don't know how to find it?
    It must be half way between the mass centres of the two arms taken separately. Where are they?
     
  7. May 1, 2014 #6
    I don't know how they got it. It makes sense it would be there, I was looking for a formula possibly.
     
  8. May 1, 2014 #7

    haruspex

    User Avatar
    Science Advisor
    Homework Helper
    Gold Member
    2016 Award

    Did you read my spoiler hint?
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?
Draft saved Draft deleted