Determine the Acceleration of the plate for which there is no Force

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Homework Help Overview

The problem involves a right-angle bar that is hinged to a vertical plate and is prevented from rotating by pegs. The objective is to determine the acceleration of the plate such that no force is exerted on the bar by the pegs. The context includes forces acting on the bar and moments about different points.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss summing forces in both x and y directions and taking moments about different points to solve for the acceleration. There is an exploration of why different approaches yield different results, particularly regarding the significance of the center of mass in calculations.

Discussion Status

Some participants have provided insights into the importance of choosing the correct point for taking moments, particularly emphasizing the center of mass. There is ongoing exploration of the reasoning behind the location of the center of mass and its implications for the calculations.

Contextual Notes

Participants express uncertainty about the method for determining the center of mass and seek clarification on the formulas or reasoning used to find it. There is a mention of a spoiler hint that may contain additional guidance.

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Homework Statement


The right-angle bar with equal legs weighs 6.0 lb and is freely hinged to the vertical plate at C. The bar is prevented from rotating by the two pegs A and B fixed to the plate. Determine the acceleration a of the plate for which no force is exerted on the bar by A either B peg or .

I have attached an image of the question

Homework Equations


The Attempt at a Solution



I'm pretty sure this is a striaghtforward question but I think I'm missing something.

First I summed the forces in the x and y direction.

ƩFy = may = Cy - mg

Cy = mg

ƩFx = max = Cx

Then I took the moment about the origin. I assigned the origin as being inbetween A and B.

And I found the center to be (2,6)

ƩM = -1/6*mg -8/12*Cx + 8/12*Cy

Cx = 3/4*mg

ax = a = Cx/m = [(3/4)mg]/m = (3/4)g

But the answer should be 3g. Where am I making my mistake?

Any help would be appreciated.
 

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I looked over the question again and this time I took the moment at the center of mass (2,6)

Hence:

ƩMG = 0 = -2/12*Cx + 6/12*Cy

Cx = 3mg

a = Cx/m = 3mg/m = 3g

So, I've got the right answer, but why didn't it work when I took the moment about the Origin I assigned? What is the significance of taking the moment about the center of the shape?
 
Acceleration of a system is always acceleration of the center of mass of the system. Since your force Cx is at the hinge and not at the center of mass, you must choose the center of mass as your rotation point when summing moments. Or use the concept of the pseudo force "-ma" applied at the center of mass, then you can sum moments equal 0 about any point.
 
how did you find the center to be at (2, 6)?
 
mgarci88 said:
how did you find the center to be at (2, 6)?
I agree with that location. Are you asking because you disagree or because you really don't know how to find it?
It must be half way between the mass centres of the two arms taken separately. Where are they?
 
I don't know how they got it. It makes sense it would be there, I was looking for a formula possibly.
 
mgarci88 said:
I don't know how they got it. It makes sense it would be there, I was looking for a formula possibly.

Did you read my spoiler hint?
 

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