Determine the amount of energy transfer by work in btu

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SUMMARY

The discussion focuses on calculating the energy transfer by work in a polytropic process involving 14.5 lb of air, transitioning from an initial state of 80 lbf/in² and 4 ft³/lb to a final state of 20 lbf/in² and 11 ft³/lb. The correct polytropic exponent, n, is determined using the formula n = ln(p1/p2)/ln(v1/v2), resulting in a positive value of +1.3704. The work done, calculated using W = (p2v2 - p1v1)/(1-n), yields 563714.9 lbf-ft, which converts to 725 Btu. The discrepancy in n values arises from incorrect application of the formula.

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Homework Statement


A closed system consisting of 14.5 lb of air undergoes a polytropic process from p1 = 80 lbf/in2, v1 = 4 ft3/lb to a final state where p2= 20 lbf/in2, v2 = 11 ft3/lb. Determine the amount of energy transfer by work, in Btu, for the process


Homework Equations


W = ∫v1v2p dv = ∫v1v2 c/vn dv

The Attempt at a Solution



Using the relationship p1v1n = p2vn2

I solved for n with:

n = ln(p2/p1)/ln(v2/v1) which gives me

n = -1.3704 but other people I've spoken to have gotten +1.3704 which, when used in:

W = p2v2 - p1v1/(1-n)

gives me 563714.9 lbf-ft, which then gives me 725 Btu when converted to Btu.

Why do I get -1.3704 instead of a positive?
 
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You did not solve for n correctly. It's
n = ln(p1/p2)/ln(V1/V2) > 0.
 

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