The pinion gear A has a constant angular acceleration of 3 rad/s^2. Determine the angular velocity and angular displacement of the output shaft C @ t=2s starting from rest. The shaft is fixed to B and turns w/ it.
A has a radius of 35mm, B has a radius of 125mm, C is unkhown radius
just a note. when i use a = angular acceleration
The Attempt at a Solution
First I found the angular velocity at A
w(a) = w(0) + at where w(0) = 0, a = 3rad/s^2, t=2
Next I transferred it to the bigger gear B
w(a)r(a) = w(b)r(b) where w(a) = 6rad/s, r(a) = 35mm, r(b) = 125mm
there fore w(b) = 1.68 ras/s
a(a)r(a) = a(b)r(b) where a(a) = 3rad/s^2, r(a) = 35mm, r(b) = 125mm
therefore a(b) = .84 ras/s^2
Since B & C are conected is a(b) = a(c).
I then tried to find the angular displacement @ c
a d(pheta) = w dw which gives .84pheta = .5w(b)^2
pheta = 1.68 rad.
But 1.68 rad is the angular velocity at B. Is this correct