Determine the base unit for the magnetic flux

[aaron86]

Homework Statement

The e.m.f E of a battery is given by $$E = \frac{P}{I}$$ where P is the power supplied from the battery when current I flows through it. An e.m.f. $${E_c}$$ can also be induced in a coil when the magnetic flux, $$\Phi$$, associated with it changes with time, t, as expressed by $${E_c} = \frac{{d\Phi }}{{dx}}$$. Determine the base unit for the magnetic flux.

Answer is $$kg{m^2}{A^{ - 1}}{s^{ - 2}}$$

Homework Equations

$$E = \frac{P}{I} = \frac{{kg{m^2}{s^{ - 2}}}}{{A \cdot s}}$$

The Attempt at a Solution

I tried to integrate $$E = \frac{P}{I} = \frac{{kg{m^2}{s^{ - 2}}}}{{A \cdot s}}$$ but was stuck at getting the answer. Please help
Thanks!

 

[Dadface]

There is no need to integrate,just rearrange your equation to make phi the subject then insert the base units and tidy it up.

 

[rl.bhat]

Power = workXtime= kg*m^2*s^-3
flux = Pxs/I.
Now find the final unit.

 

[Dadface]

Flux=Px/I.You have the right units for P,x is s and I is A

 

[aaron86]

Thanks for the replies, however, aren't we suppose to extract information that is provided by the question?

How do you guys deduce the answer from $${E_c} = \frac{{d\Phi }}{{dx}}$$ ?

 

[Dadface]

Phi=Ex