Determine the coefficient of performance of this cycle

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1. May 6, 2016

Nemo's

1. The problem statement, all variables and given/known data
In an ideal refrigeration cycle, the temperature of the condensing vapour is 40oC and the temperature during evaporation is -20oC. Determine the coefficient of performance of this cycle for the working fluids; R12 and ammonia.

2. Relevant equations
C.O.Pc = TL/(TH-TL)

3. The attempt at a solution
C.O.Pc= ((-20+273)/(40--20))
= 4.2
I don't understand how the working fluid would affect the results of the C.O.Pc (where c stands for carnot efficiency)

2. May 7, 2016

jim hardy

Last edited by a moderator: May 7, 2017
3. May 7, 2016

Nemo's

Thanks you for the helpful material you attached.
From the second attachment I concluded that COPR=(h1-h4)/(h2-h1) so I was able to get h1 from the tables at -20οC. for R12 h1=178.73 and similarly I got h2=74.59. However,I don't know the temperature at 3 or 4 so I can't get h4. What should I do?

4. May 7, 2016

SteamKing

Staff Emeritus
The temperature at 4 is going to be the same TL as in the ideal Carnot cycle.

Do like Jim suggests, and look at the worked example he attached in Post #2.

5. May 7, 2016

jim hardy

1. Go back to original question
Ideal cycle, eh ?
That's what is represented in the T-S diagram above,
working fluid enters evaporator as liquid-vapor mix at saturation pressure and leaves as saturated vapor at same pressure, as stated by phrase "4-1 constant pressure heat addition" and as shown by proximity to saturation line on the T-S diagram ...
that sounds to me like constant temperature
What do you think from looking at the chart ?

in their ideal cycle chart they don't show any superheat so i'd assume saturation temperature on both ends of the evaporator, just different quality.
Isn't that what is the "x" is here , fraction of vapor ?

2. so i think if you know t at 1 you know t at 4. What do you think ?

It is helpful to remember refrigerators work by heat of vaporization
and imagine yourself inside a tiny submarine riding along through the pipes

3. so - what goes on in the condenser ? Heat of vaporization is rejected....
First it cools the superheated compressor discharge , point 2 to saturation line,
then it rejects heat of vaporization at constant pressure again as stated, that's saturation line to other side of saturation curve point 3. Between the two sides of the saturation line it is just giving up heat of vaporization, and that has to be at saturation temperature... I think you probably know T at 3.....

4. Print yourself several copies of that T-S chart and think your way around the circuit,
writing on each segment your own words about what is going on. When you get the words boiled down to a concise summary and it "feels right" you will feel an upwelling sense of accomplishment. Probably you'll improve on it after a night's sleep.

Just a couple days ago i charged a friend's car airconditioner.
When they're low on freon they can't liquefy in the condenser
so no liquid enters the evaporator
meaning there can't be much absorbtion of heat in the evaporator because there's no vaporization going on in there anymore
and the air comes out of the dashboard vents warm. Point 1 is in superheat.
It is enlightening to feel the air get cooler as the compressor's suction pressure comes up , which is counterintuitive ...
but what's happening is it's coming out of superheat and is approaching saturation pressure for the cabin air temperature.

In a real airconditioner they want a small amount of superheat at evaporator outlet to assure the compressor doesn't ingest incompressible liquid
and they want a small amount of subcooling at condenser outlet to assure you've given up all the heat of vaporization
but those practicalities aren't shown on the ideal diagram.