Can the Carnot Reversible Machine Challenge the Second Law of Thermodynamics?

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SUMMARY

The discussion centers on the Carnot reversible machine and its relationship to the Second Law of Thermodynamics. It establishes that no machine can exceed the efficiency of the Carnot machine, as illustrated by a thought experiment involving both reversible and irreversible machines connected to thermal reservoirs. The participants argue that if the Carnot machine were assumed to be less efficient than an irreversible machine, it would lead to a contradiction of the Second Law. The conclusion emphasizes that the work produced by a heat engine, when supplied to a Carnot refrigerator, will always result in a net heat transfer that adheres to the Second Law.

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  • Understanding of the Second Law of Thermodynamics
  • Familiarity with Carnot cycle principles
  • Knowledge of heat engines and refrigerators
  • Basic thermodynamic concepts such as heat transfer and efficiency
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  • Study the Carnot cycle and its implications for thermodynamic efficiency
  • Explore the principles of irreversible processes in thermodynamics
  • Learn about real-world applications of the Second Law of Thermodynamics
  • Investigate the concept of thermal reservoirs and their role in thermodynamic cycles
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Chacabucogod
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I was reading Cengel's thermodynamics and noticed that he uses a thought experiment to show that there is no machine that is more efficient than the Carnot reversible machine. He says that both a reversible machine and an irreversible machine are connected to high and low temperature deposits, and that they both receive Qh from the high temperature deposit. He next assumes that the irreversible machine is more efficient than the Carnot machine, and reverses the Carnot machine so that it works as a "refrigerator". The refrigerator is going to be providing Qh to the hot deposit and the irreversible machine will receive Qh so that the deposit can be taken away and both of the machines connected. Then the machines would not have two deposits to complete the cycle and it would not agree with the second law.

Now if I don't assume that the Carnot machine is less efficient than the irreversible machine and reverse it wouldn't the second law be broken too? Or would the Qh that the Carnot machine is providing be less than the required by they second machine?

Thank you
 
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Chacabucogod said:
The refrigerator is going to be providing Qh to the hot deposit and the irreversible machine will receive Qh so that the deposit can be taken away and both of the machines connected. Then the machines would not have two deposits to complete the cycle and it would not agree with the second law.
Another way to see it is with both reservoirs connected, and the combination of the heat engine and the Carnot refrigerator as one machine. You would then get a heat engine that transfers heat from the cold reservoir to the hot one, without any external input. This is an obvious violation of the 2nd law.

Chacabucogod said:
Now if I don't assume that the Carnot machine is less efficient than the irreversible machine and reverse it wouldn't the second law be broken too? Or would the Qh that the Carnot machine is providing be less than the required by they second machine?
Remember that there is "work" between the two machines. If the heat engine's efficiency is equal or less than a Carnot engine, then the work produced by it, when supplied to the Carnot refrigerator, will lead to a transfer of heat from cold to hot reservoirs (by the Carnot refrigerator) that is less than the consumption of heat from the hot reservoir by the heat engine.
 

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