determine the magnitude of the frictional force acting on the box on the plane
Homework Equations
f=ma
The Attempt at a Solution
no clue. help ??
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#2
flyingpig
2,574
1
*imagines there is a support for the slanted green line*
Free Body Diagram, let's go. And we should do this question before you tackle on that tension problem
#3
physicsgurl12
184
0
the tension was part a. this is part b. the force diagram would be the same as the other but without the force of the rope.
#4
Zula110100100
250
0
Since we are determining friction the equation for the force of friction is required, and in this case so is the angle...
#5
physicsgurl12
184
0
Zula110100100 said:
Since we are determining friction the equation for the force of friction is required, and in this case so is the angle...
well there isn't an angle?
#6
Zula110100100
250
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I am confused then, can you please give us all known variable? If it is the same as the other thread is the angle not also the same at 60degrees?
#7
physicsgurl12
184
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the whole problem reads this. two 10 kilogram boxes are connected by a massless string that passes ocer a massless frictionless pulley as shown above( this would be the picture on the other problem) The boxes remaine at rest, with one on the right hanging vertically and the one on the left 2.0meters from the bottom of an inclined plane that makes an angle of 60 degrees with the horizontal. The coefficients of kinetic friction and static friction between the left hand box and the plane are .15 and .30 respectively. You may use g=10m/s^2, sin60=.87, and cos60=.50
a. what is the tension T in string
b. On the diagram below draw and label all forces acting on the box that is on the plane.
c. determine the magnitude of the frictional force acting on the box on the plane.
#8
Zula110100100
250
0
So the angle is indeed 60, I would start by determining the forces on the box in each direction(i.e. parallel to the plane, normal to the plane)
