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The Question is:

A pendulum oscillating on the moon has the same period as a(n) 3.66 m pendulum oscillating on Earth. If the moon’s gravity is one-sixth of Earth’s gravity, ﬁnd the length of the pendulum on

the moon.

Attempt:

T

_{moon}= T

_{earth}

T

_{earth}= 2∏√(L/g)

T

_{earth}= 2∏√(3.66m/9.8m/s) = 3.8397891 s-1 = T

_{moon}

g

_{moon}(T/2∏)

^{2}= L

(9.8/6)( 3.8397891/2∏)

^{2}= L = 59.419563 m

Somewhere, I've gone wrong. Any guidance would be much appreciated