So I'm working on homework, and encountered this problem. I thought I understood what to do, but I'm not getting the right answer. I'm so frustrated I decided to create an account, so this is my first post. I'll do my best to adhere to the PF format of questions.(adsbygoogle = window.adsbygoogle || []).push({});

The Question is:

A pendulum oscillating on the moon has the same period as a(n) 3.66 m pendulum oscillating on Earth. If the moon’s gravity is one-sixth of Earth’s gravity, ﬁnd the length of the pendulum on

the moon.

Attempt:

T_{moon}= T_{earth}

T_{earth}= 2∏√(L/g)

T_{earth}= 2∏√(3.66m/9.8m/s) = 3.8397891 s-1 = T_{moon}

g_{moon}(T/2∏)^{2}= L

(9.8/6)( 3.8397891/2∏)^{2}= L = 59.419563 m

Somewhere, I've gone wrong. Any guidance would be much appreciated

**Physics Forums | Science Articles, Homework Help, Discussion**

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Determine the length of a pendulum on the moon

**Physics Forums | Science Articles, Homework Help, Discussion**