So I'm working on homework, and encountered this problem. I thought I understood what to do, but I'm not getting the right answer. I'm so frustrated I decided to create an account, so this is my first post. I'll do my best to adhere to the PF format of questions.(adsbygoogle = window.adsbygoogle || []).push({});

The Question is:

A pendulum oscillating on the moon has the same period as a(n) 3.66 m pendulum oscillating on Earth. If the moon’s gravity is one-sixth of Earth’s gravity, ﬁnd the length of the pendulum on

the moon.

Attempt:

T_{moon}= T_{earth}

T_{earth}= 2∏√(L/g)

T_{earth}= 2∏√(3.66m/9.8m/s) = 3.8397891 s-1 = T_{moon}

g_{moon}(T/2∏)^{2}= L

(9.8/6)( 3.8397891/2∏)^{2}= L = 59.419563 m

Somewhere, I've gone wrong. Any guidance would be much appreciated

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# Homework Help: Determine the length of a pendulum on the moon

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