Determine the magnitude of the minimum acceleration

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Homework Help Overview

The problem involves a scenario where a 76-kg individual is attempting to escape from a jail window using a rope made of sheets that can only support a maximum weight of 58 kg. The objective is to determine the minimum acceleration required for the individual to descend safely using the rope.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the forces involved, particularly tension and weight, and question how to define the positive direction for acceleration. There is also uncertainty about whether to use the mass of the individual or the mass that the rope can withstand in calculations.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the problem and clarifying the definitions of mass and force. Some guidance has been offered regarding the signs in the equations based on the chosen direction of acceleration.

Contextual Notes

There is a noted confusion regarding the distinction between mass and weight, as well as the implications of the rope's weight capacity on the calculations. Participants are considering the constraints of the problem as they relate to the forces acting on the individual and the rope.

tristanmagnum
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Homework Statement



A 76-kg petty thief wants to escape from a third-story jail window. Unfortunately, a makeshift rope made of sheets tied together can support a mass of only 58 kg.Determine the magnitude of the minimum acceleration at which the thief can descend using the rope.

Homework Equations



i think T-mg=ma?

The Attempt at a Solution


i know tension would be the upward force and mg (weight) would be the upward force correct?
 
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The signs are going to depend on how you define the positive direction. Your equation is fine if the aceleration a is defined upward (so expect a negative result).
 
haruspex said:
The signs are going to depend on how you define the positive direction. Your equation is fine if the aceleration a is defined upward (so expect a negative result).

would i use the mass of the man or the mass that the sheet can with stand?
 
tristanmagnum said:
would i use the mass of the man or the mass that the sheet can with stand?
The question is not quite right. It should say that the sheets can withstand a weight of 58g N. Mass is not force.
 
What would the tension be if a man of 58 kg chose to rest from it?
 

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