Determine the Maximum Tensile and Compressive Stresses in the Beam

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SUMMARY

The discussion focuses on calculating the maximum tensile and compressive stresses in a beam subjected to vertical forces. The participant utilized the formula σ = P/A ± My/Ix, applying the parallel axis theorem to determine the moment of inertia, Ix. The centroid was calculated to be at coordinates (4.5 in, 3 in). The final results indicated maximum tensile stress of 8.82 ksi and maximum compressive stress of 14.72 ksi, with clarification needed on the correct y-values for stress calculations.

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Homework Statement


Two vertical forces are applied to a beam of the cross section shown. Determine the maximum tensile and compressive stresses in portion BC of the beam

I have attached an image of the question

Homework Equations



σ = P/A +/- My/Ix

Ix = Ix + Ad2 ---> parallel axis theorem

The Attempt at a Solution



I calculated the centroid to be:

x = 4.5 in

y = 3 in

I did this by dividing the shape into two rectangles, determining the centers of those rectangles from an arbitrarily assigned origin, O, which I assigned to be at the bottom left of the lower rectangle.

I then used the parallel axis theorem to calculate the Inertia, Ix

P = 0 because the sum of the forces is 0.

M is the greatest moment value, which I found to be 600 kip-in.

My confusion is how do I determine the y value? I believe that the greatest tensile and compressive stresses would be at the bottom and top of the bar respectively, but my notes indicate that the correct y-values are 3 in for the tensile stress and 5 in for the compressive stress. I had thought that the y values was from the centroid of the cross-section which makes me think it should be 3 in for the max compressive and tensile forces.

Can anyone clarify this for me?

I know the final answers are

8.82 ksi T

14.72 ksi C
 

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