Determine the net charge contained within the cube

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SUMMARY

The discussion focuses on calculating the net charge contained within a cube with a side length of 3.7 m, where the electric field on the top face is -40 N/C and on the bottom face is +10 N/C. The relevant equations include the electric flux equation (flux = E x A) and the relationship between flux and charge enclosed (flux = charge enclosed / permittivity constant). The correct calculation of the electric flux results in a value of 684.5, leading to the determination of the net charge using the permittivity constant of 8.854E-12 F/m.

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  • Knowledge of the permittivity constant (epsilon-naught) and its significance in electrostatics.
  • Ability to perform basic algebraic manipulations to solve equations.
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  • Learn how to apply Gauss's Law to different geometries, including spheres and cylinders.
  • Explore the implications of the permittivity constant in various materials and its role in capacitance.
  • Practice solving problems involving electric fields and charges using real-world scenarios.
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Homework Statement


At each point on the surface of the cube shown in the figure, the electric field is parallel to the z axis. The length of each edge of the cube is 3.7 m. On the top face of the cube = -40 N/C, and on the bottom face of the cube = +10 N/C. Determine the net charge contained within the cube.






Homework Equations



flux = E x A

flux = charge enclosed/ permittivity constant (epsilon-naught)



The Attempt at a Solution



I first plugged the numbers to find the flux of the the ends of the cube, then the plugged that into the second equation to find the charge enclose, but I got a really small number that wasn't right.
 
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What number you got?
 
-6x10^13 I meant a really big number.
 
I am getting ..6. ..E-9.

Flux is 684.5 (simply adding two together)
and then electric constant is 8.854E-12
 
Ahh, and then its negative, I didn't add the two together I was only using one. Dumb mistake, but thank you soo much!
 

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