Determine the position of the slider on the pot

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SUMMARY

The discussion focuses on determining the position of a 10kΩ potentiometer in a circuit with a 5kΩ load, specifically when the voltage across the load is 3V. Participants clarify that the potentiometer can be represented as two resistors in series, denoted as x10kΩ and (1-x)10kΩ, where x varies from 0 to 1. The voltage divider formula is essential for calculating the output voltage, which involves understanding the relationship between the resistances and the load. The key takeaway is that the output voltage can be expressed using the combined resistance of the potentiometer and the load in parallel.

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  • #31
Harrison01 said:
I just can't get in my thick skull...

Refer to the diagram in post #4.
 
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  • #32
gneill said:
:confused: What happened to the equation you spent so much time deriving? x should be a unitless number, representing the fraction of the potentiometer that is Ra.

Ok i understand that x and (x-1) are unitles numbers as we yet don't know their value but we do know that their value sums up to 10kohms. We therefore need to work out the ratio. We know we have a Vout of 3v and that Rl is 5kohms. I just can't seem to understand how we use all this data to give us the value of Ra or Rb which will then give us the opposing figure.
 
  • #33
Ra is x*R. Rb is (1-x)R. R is the value of the potentiometer, 10000 Ohms.

Ra + Rb = R

x*R + (1-x)*R = R

x is just a value that "cuts" the potentiometer into two pieces. The two pieces sum to the whole.
 
  • #34
I haven't touched anything like this in years and was following this through ok till i hit post 21 and 22.

Could someone please explain how we specifically get the (Rb*Rl)+(Ra*Rl)+(Rb*Ra) part of Vout= E* Ra*Rl/[(Rb*Rl)+(Ra*Rl)+(Rb*Ra)]

I just can't see why its Rb X Rl + the rest..

Could someone show or explain how these 3 are derived.
I would be very grateful.
 
  • #35
braceman said:
I haven't touched anything like this in years and was following this through ok till i hit post 21 and 22.

Could someone please explain how we specifically get the (Rb*Rl)+(Ra*Rl)+(Rb*Ra) part of Vout= E* Ra*Rl/[(Rb*Rl)+(Ra*Rl)+(Rb*Ra)]

I just can't see why its Rb X Rl + the rest..

Could someone show or explain how these 3 are derived.
I would be very grateful.

Expand the expression for the output of the voltage divider using the given components.
 

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