Determine torque required to move load

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SUMMARY

The discussion focuses on calculating the torque required for two electric motors to move a 100 lbs load on a flat surface using 8-inch diameter wheels. Key calculations include determining acceleration, maximum speed, and the necessary torque based on the vehicle's travel distance and time. The final torque calculation yields approximately 1.6856 N·m, derived from the force of 16.591 N acting at a radius of 0.1016 m. The discussion emphasizes the importance of considering acceleration and friction in torque calculations.

PREREQUISITES
  • Understanding of basic physics concepts such as force, mass, and acceleration.
  • Familiarity with torque calculations and the formula Torque = Force x Radius.
  • Knowledge of unit conversions, particularly between imperial and SI units.
  • Experience with electric motor specifications, including RPM and gearbox functions.
NEXT STEPS
  • Research the impact of rolling friction on torque calculations for electric motors.
  • Learn about gearbox types and their effect on torque and RPM in electric motors.
  • Explore the use of simulation software for modeling motor performance under load.
  • Investigate the principles of energy conservation in mechanical systems.
USEFUL FOR

Mechanical engineers, robotics enthusiasts, and anyone involved in designing electric motor systems for moving loads will benefit from this discussion.

lsvaladez
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Trying to figure out how much torque an electric motor would need to move a load of 100lbs on a flat surface. The device would use two electric motors attached to a 8 inch diameter wheel (each motor is attached to a 8 inch wheel).
 
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Welcome to PF.

Only the energy needed to accelerate the mass must come from the motor.
What is the maximum speed required?
To enable us to calculate the wheel torque required, we need to know how far the vehicle will travel, and how much time does it have to get there?

A cheaper, low-torque, high-RPM motor could be used if the motor has a gearbox, that would slow the wheel speed and increase the torque available to drive the wheel.
 
lsvaladez said:
Trying to figure out how much torque an electric motor would need to move a load of 100lbs on a flat surface. The device would use two electric motors attached to a 8 inch diameter wheel (each motor is attached to a 8 inch wheel).
Are you using the wheels to drive a conveyor belt carrying a 100 lbf load, or something else, maybe this is a buggy carrying 100 lbf? Either way, acceleration and various forms of friction should be considered to determine the minimum output.
 
Is this homework? If so, we can move it.

A diagram of what you are trying to do would be very helpful because your description is unclear. If you have no information on rolling friction, you need to provide the necessary information so that we can help you estimate the rolling friction. You need to describe the speed, distance, move time, and acceleration in order to calculate acceleration torque. You need to know the maximum speed in order to properly specify the motor and reducer.
 
Baluncore said:
Welcome to PF.

Only the energy needed to accelerate the mass must come from the motor.
What is the maximum speed required?
To enable us to calculate the wheel torque required, we need to know how far the vehicle will travel, and how much time does it have to get there?

A cheaper, low-torque, high-RPM motor could be used if the motor has a gearbox, that would slow the wheel speed and increase the torque available to drive the wheel.
Hello,

Let’s say the device needs a max velocity of 5mph, and we want it to travel around 30ft in 10 seconds.
 
I assume you must stop when you get there, and have no brakes, so you will use the motor to brake. That makes the problem symmetrical.

Accelerate for 5 seconds, then decelerate for 5 seconds, to get there in 10 sec. 15 feet in the first 5 seconds, then 15 feet in the last 5 sec.
We know; s = ½ * a * t2 ; so can calculate the acceleration.
a = 2 * s / t2
a = 2 * 15 / 52
a = 30 / 25 = 1.20 ft⋅s-2

The speed limit is 5 mph = 7.333 ft/sec.
What will the velocity be after 5 seconds.
v = 1.2 * 5 = 6 ft/sec.
So it is below the speed limit.

I think I would use SI units for the next bit.
 
SI units.
Time, t = 5.000 sec
Dist, d = 15' * 0.3048 = 4.572 m
Accel, a = 2 * d / t^2 = 0.3658 m/s/s
Vmax, v = a * t = 0.3658 * 5 = 1.8288 m/s
Mass, m = 100 lb * 0.4536 = 45.36 kg
Force, f = m * a = 16.591 N, (newtons)
Radius, r = 4" = 0.1016 m
Torque = f * r = 1.6856 N.m
Energy = 0.5 * m * v^2 = 75.8535 J, (joules)
 

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