Determine whether the function f(x) is continuous

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Homework Help Overview

The discussion revolves around determining the continuity of the piecewise function f(x) at the point x = 1. The function is defined differently for values less than, equal to, and greater than 1, prompting an analysis of its behavior at this critical point.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss finding the left-hand and right-hand limits as x approaches 1. There are questions about the correctness of the calculated limits and how they relate to the definition of continuity.

Discussion Status

The discussion is ongoing, with participants sharing their limit calculations and referencing the definition of continuity. Some guidance has been offered regarding the conditions for continuity, but there is no explicit consensus on the conclusions drawn from the limits.

Contextual Notes

There are indications of confusion regarding the limits and their implications for continuity, particularly concerning the values of f(x) at specific points. Participants are also exploring the implications of continuity at other points, such as x = 0.

naspek
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Homework Statement



Given that

f(x) = { x + 1 ......; if x < 1
...{ 2 .....; if x = 1
...{ [4(x-1)] / (x^2 - 1) ; if x > 1

Determine whether the function f(x) is continuous at x = 1

i don't know how to start..
can someone give me an idea to start..
 
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Try finding the limit of f as x approaches 1 from the left and the right (that is, with values of x < 1 and values of x > 1)
 


ok.. for

[tex]\lim_{x \to 1^{-}} f(x)[/tex]

i got 0

for

[tex]\lim_{x \to 1^{+}} f(x)[/tex]

i got 2

am i got it right?
so.. how can i conclude it?
 


ok so now you have to go back to the calc one definition of continuity. the requirements were
If f is continuous at a then, these 3 facts have to hold
[tex]\lim_{x \to a^{-}} f(x) = f(a)[/tex]
[tex]\lim_{x \to a^{+}} f(x) = f(a)[/tex]
[tex]\lim_{x \to a} f(x) = f(a)[/tex]
 


naspek said:
ok.. for

[tex]\lim_{x \to 1^{-}} f(x)[/tex]

i got 0
For x< 0, f(x)= 1+ x. Are you saying that [itex]\lim_{x\to 0} 1+ x= 0[/itex]?

for

[tex]\lim_{x \to 1^{+}} f(x)[/tex]

i got 2

am i got it right?
so.. how can i conclude it?
This function is continuous at x=0 only if the limit there exists and is equal to f(0). The limit itself exist only if those two one sided limits are the same.
 

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