Determing the kinetic energy of an electron

  • Thread starter Turion
  • Start date
  • #1
143
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Homework Statement



sxvTCH3.png


Homework Equations





The Attempt at a Solution



KEi + PEi = KEf
2.4 x 10-19 + e(1) = KEf
KEf = 4.002 x 10-19 J

So option c would be correct, right? Thank you in advance.
 

Answers and Replies

  • #2
143
2
b5LwGCD.png


This one is a trick question, right? It would need 0 kinetic energy because the electric field itself would move the electron to the left until it reaches point C.
 
  • #3
143
2
This one doesn't even make sense to me. How can the electron go back to plate D if plate D has the higher voltage?

CA7nl94.png
 
  • #4
nasu
Gold Member
3,775
432

Homework Statement



sxvTCH3.png


Homework Equations





The Attempt at a Solution



KEi + PEi = KEf
2.4 x 10-19 + e(1) = KEf
KEf = 4.002 x 10-19 J

So option c would be correct, right? Thank you in advance.

No. The electron is repelled by the negative plate so its KE decreases when it moves from B to A.
And it's easier if you work in eV directly.
The potential difference between B and A is 1 V so the change in potential energy is 1eV.

And I think you are supposed to post one problem per topic.
 

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