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Determing the kinetic energy of an electron

  1. Sep 29, 2013 #1
    1. The problem statement, all variables and given/known data

    sxvTCH3.png

    2. Relevant equations



    3. The attempt at a solution

    KEi + PEi = KEf
    2.4 x 10-19 + e(1) = KEf
    KEf = 4.002 x 10-19 J

    So option c would be correct, right? Thank you in advance.
     
  2. jcsd
  3. Sep 29, 2013 #2
    b5LwGCD.png

    This one is a trick question, right? It would need 0 kinetic energy because the electric field itself would move the electron to the left until it reaches point C.
     
  4. Sep 29, 2013 #3
    This one doesn't even make sense to me. How can the electron go back to plate D if plate D has the higher voltage?

    CA7nl94.png
     
  5. Sep 29, 2013 #4
    No. The electron is repelled by the negative plate so its KE decreases when it moves from B to A.
    And it's easier if you work in eV directly.
    The potential difference between B and A is 1 V so the change in potential energy is 1eV.

    And I think you are supposed to post one problem per topic.
     
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