- #1

- 143

- 2

## Homework Statement

## Homework Equations

## The Attempt at a Solution

KE

_{i}+ PE

_{i}= KE

_{f}

2.4 x 10

^{-19}+ e(1) = KE

_{f}

KE

_{f}= 4.002 x 10

^{-19}J

So option c would be correct, right? Thank you in advance.

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- Thread starter Turion
- Start date

- #1

- 143

- 2

KE

2.4 x 10

KE

So option c would be correct, right? Thank you in advance.

- #2

- 143

- 2

This one is a trick question, right? It would need 0 kinetic energy because the electric field itself would move the electron to the left until it reaches point C.

- #3

- 143

- 2

- #4

nasu

Gold Member

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## Homework Statement

## Homework Equations

## The Attempt at a Solution

KE_{i}+ PE_{i}= KE_{f}

2.4 x 10^{-19}+ e(1) = KE_{f}

KE_{f}= 4.002 x 10^{-19}J

So option c would be correct, right? Thank you in advance.

No. The electron is repelled by the negative plate so its KE decreases when it moves from B to A.

And it's easier if you work in eV directly.

The potential difference between B and A is 1 V so the change in potential energy is 1eV.

And I think you are supposed to post one problem per topic.

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