r = 2
r^2 = 9sin(2theta)
Find the 4 points of intersection
The Attempt at a Solution
Since r = 2, 4 = 9sin(2theta)...
4/9 = sin(2theta)
Taking the inverse of 4/9 only gives me one answer on the calculator (obviously), and I do not know where to attain the 3 other points. (also, is there a way to do this without a calculator/calculus?) - IE 4/9 = 2sin(theta)cos(theta), although I do not see how this helps.