Determining a Subspace: Problem and Conditions

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SUMMARY

The discussion centers on determining whether a given set S is a subspace by verifying three essential conditions: the inclusion of the zero vector, closure under addition, and closure under scalar multiplication. Participants debated the implications of the zero vector's presence in S, particularly when modifying elements of S, such as changing 2x-1 to 2y-1. The necessity of proving closure under addition and scalar multiplication was also questioned, with emphasis on the importance of rigorous mathematical proof over intuitive reasoning.

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  • Understanding of vector spaces and subspaces
  • Familiarity with the properties of zero vectors in linear algebra
  • Knowledge of closure properties in vector spaces
  • Basic skills in mathematical proof techniques
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Students of linear algebra, mathematicians, and educators seeking to deepen their understanding of vector spaces and the criteria for subspaces.

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The problem is attached. I need to determine if it's a subspace.
So it must satisfy 3 conditions:
1) 0 vector is in S
2) if U and V are in S then U+V is in S
3) if V is in S, then cV where c is a scalar is in S


For the 1st condition:
I said the 0 vector is not in S, but I'm not sure if I'm understanding it correctly. For this problem when we say the 0 vector is in S are we asking if we have x=0 does that give us the 0 vector?


Let's say we changed the bottom element to 2y-1 instead of 2x-1. And if x and y are in R.
For this case, the 0 vector would be in S right? We can have x=0 and y=1/2 which gives the 0 vector?
 

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Another question I have is for another problem (I attached this in this post). My book is trying to prove that S is not closed under addition and scalar multiplication. I don't understand why it's necesasry to do that.
Can't you just look at it and see that if the 0 vector is in S, then that means x1=0 and x3=0, but x1+x3=0+0≠-2, which means the 0 vector isn't in S. What is the point of proving the more complicated steps?
 

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Bump, anyone?
 

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