I Determining continuity using Gauss' law

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Gauss' law effectively determines the discontinuity of the electric field at points on a surface charge, where the normal component of the electric field experiences a jump proportional to the surface charge. For non-singular volume-charge distributions, there are no discontinuities in the electric field, as confirmed by the Gauss pill-box argument. The discussion raises the possibility of using alternative methods to prove this concept without relying solely on Gauss' law. Clarifications regarding these concepts are anticipated in future posts. Understanding these principles is crucial for analyzing electric fields in various charge distributions.
Mike400
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I know how Gauss law helps us to calculate the discontinuity at a point on the surface of a surface charge.

Similarly using Gauss law, is there a way to determine the continuity at other points of electric field due to a surface charge or the continuity at all points of electric field due to a volume charge?
 
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I don't understand the question. If there's a surface charge, the normal component of the electric field jumps by that surface charge (modulo some factors depending on the system of units). If you have a non-singular volume-charge distribution there are no discontinuities.
 
vanhees71 said:
If you have a non-singular volume-charge distribution there are no discontinuities.
Can we prove it using Gauss law?
 
Sure, just use the "Gauss pill-box argument" to a situation where you have a non-singular charge distribution.
 
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Thanks a lot... Anyway I have to clear some confusions regarding that. I will post my confusions tomorrow... I am so sleepy
 
vanhees71 said:
If you have a non-singular volume-charge distribution there are no discontinuities.
Are there any other simple methods to prove it without using Gauss law?
 
Thread 'Why higher speeds need more power if backward force is the same?'

Thread 'Why higher speeds need more power if backward force is the same?'

Power = Force v Speed Power of my horse = 104kgx9.81m/s^2 x 0.732m/s = 1HP =746W Force/tension in rope stay the same if horse run at 0.73m/s or at 15m/s, so why then horse need to be more powerfull to pull at higher speed even if backward force at him(rope tension) stay the same? I understand that if I increase weight, it is hrader for horse to pull at higher speed because now is backward force increased, but don't understand why is harder to pull at higher speed if weight(backward force)...
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