the amount of charge flwoing past a point in a current in a circuit is found to vary with time as follows:
Q(t) = 100[e^(+t/100) + 0.01t^2]
what is the current flowing at t = 10 seconds?
i am supposed to get 47.2 amperes
C = Q/V ---> Q = CV where C is capacitance, V is electric potential, Q is charge
V = IR ----> I = V/R = dW/dt where R is resistance, W is work, t is time
The Attempt at a Solution
first solve the function in terms of t = 10 seconds
Q(10) = 100[e^(+10/100) + 0.01(10^2)] = 100[ 1.105 + 1] = 100(2.105) = 210.5 coulombs
since Q = CV and V = IR ---> Q = CIR now if i let Q = 210.5 coulombs, i don't have values for R or C, i'm solving for I.
am i using the wrong approach entirely or the wrong equation?