Determining ΔE and λ of an Electron Transition

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SUMMARY

The discussion focuses on calculating the change in energy (ΔE) and the wavelength (λ) of a photon emitted by a hydrogen atom transitioning from the n = 6 energy level. Using Rydberg's equation, the change in energy is determined to be 1.82 x 10^-19 J. A participant questions the positivity of this energy change, suggesting an alternative calculation of -2.18 x 10^-18 J based on energy level differences. The confusion arises from the interpretation of energy changes during electron transitions.

PREREQUISITES
  • Understanding of Rydberg's formula for hydrogen spectral lines
  • Knowledge of energy levels in hydrogen atoms
  • Familiarity with the concept of photon emission and absorption
  • Basic principles of quantum mechanics related to electron transitions
NEXT STEPS
  • Study Rydberg's equation and its application to different energy levels
  • Explore the concept of energy conservation in quantum transitions
  • Learn about the relationship between energy and wavelength in photon emissions
  • Investigate the implications of positive and negative energy changes in quantum mechanics
USEFUL FOR

Students of quantum mechanics, physics educators, and anyone interested in the behavior of electrons in hydrogen atoms and the principles of photon emission.

Chandasouk
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Homework Statement



A hydrogen atom with its electron in the n = 6 energy level emits a photon of the infrared light. Calculate the change in energy of the atom and the wavelength of the photon.

Using Rydberg's equation, the change in energy is 1.82 x 10^-19J

But I do not understand why the change of energy is positive

Wouldn't \DeltaE = -2.18 x 10^-18J (1/9 - 1/36) = -1.82 x 10^-19J ?
 
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What do you calculate using Rydberg's formula?

--
methods
 


position and wavelength of any line in a given series
 


Wavelength... let's make it energy of the emitted photon, OK?

--
methods
 

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