Determining Legendre derivitives

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SUMMARY

The discussion focuses on finding the derivative of the first Legendre polynomial, P1(cos(Θ)), by substituting cos(Θ) for x in the equation P1(x) = x. The derivative is calculated using the chain rule, resulting in the expression d/dΘ P1(x(Θ)) = dP1(x)/dx * dx(Θ)/dΘ, where x(Θ) = sin(Θ). This method confirms that the derivative is -sin(Θ) when applying the appropriate substitutions and differentiation techniques.

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  • Understanding of Legendre polynomials, specifically P1(x).
  • Knowledge of differentiation techniques, including the chain rule.
  • Familiarity with trigonometric functions and their derivatives.
  • Basic calculus concepts, particularly related to derivatives with respect to variables.
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  • Study the properties and applications of Legendre polynomials in mathematical physics.
  • Learn advanced differentiation techniques, including implicit differentiation.
  • Explore recurrence relations for Legendre polynomials to understand their derivation.
  • Investigate the relationship between trigonometric functions and polynomial derivatives.
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Students and professionals in mathematics, physics, and engineering who are working with Legendre polynomials and need to understand differentiation techniques in relation to trigonometric functions.

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Determining Legendre derivitives

Homework Statement



if i need to find the derivative of the first Legendre polynomial, P1(cos\Theta) can i sub in cos\Theta for x in P1(x) = x?

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The Attempt at a Solution


if that's the case the derivative is just -sin(\Theta), which is easy enough, but if i can't do that substitution then how do i find it? if there is a recurrence relation that I am missing?
 
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that sounds fine to me base don the info you have given, but maybe you should give the whole question - also what you are differentiating with respect to is important, i assume it is theta

basically you are just using chain rule
P_1(x(\theta))

where
x(\theta) = sin(\theta)

then
\frac{d}{d \theta}P_1(x(\theta)) <br /> = \frac{d P_1(x)}{dx } \frac{d x(\theta)}{d \theta }<br /> <br />
 

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