- #1
SoConfused__
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Homework Statement
The end of a 256 Hz tuning fork has an average amplitude of 1.0 mm for 2.0 seconds. How many metres does the end of the tuning fork travel in this time.
(The answer is also given in the back of the textbook, which is 2.0m).
Homework Equations
v = f * lambda, I believe.
f = cycles/seconds
The Attempt at a Solution
Well this is what I'm thinking. One wavelength would be 4mm. To the left, rest position, right, and back at resposition. (Each time the fork vibrates left & right it goes 1mm out).
Therefore 1 cycle = 4mm (0.004m)
(2/0.004m)
So, would the period be 500 metres per s?
So how many metres does the end of the tuning fork travel in 2 seconds?
Well.. wouldn't it be 1000 metres?
The answer says 2metres though. I think I don't have an understanding of the question. If someone could explain, I would very much appreciate it. Thank you so much!