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Determining new diameter of shaft after deformation

  1. Nov 5, 2014 #1
    Hey guys, I've been having an issue with my approach to this problem. I'm stuck after I get the deformation... :

    1. The proportional portion of the tension-strain diagram for an aluminum alloy is shown in the figure (attached). The specimen used for the test gauge length of 2in and a diameter of 0.5in. If the applied load is 10 kip, determine the new diameter of the specimen. The shear modulus is G = 38 x 10 ^3 ksi.



    2. L = PL / AE


    3. (10)(2)/(1)(0.00614) = 3.2573 x 10^3
     

    Attached Files:

  2. jcsd
  3. Nov 5, 2014 #2

    SteamKing

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    It's not clear from your calculation if you have determined either A or E for this specimen. Regardless, calculating δL = PL/AE is not really what the problem is looking for, which is to calculate δD for the bar when an axial load of 10 kip is applied.
     
  4. Nov 6, 2014 #3
    Is the formula the same for finding the δD?
     
  5. Nov 6, 2014 #4

    SteamKing

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    No. Hint: look up Poisson's ratio.
     
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