Determining number of dissociated moles from concentration?

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SUMMARY

This discussion centers on determining the number of dissociated moles of ions from the concentration of salts in water, specifically focusing on sodium chloride (NaCl). Participants confirm that while there is no single formula for this calculation, the concentration definition (c=n/V) can be applied directly for salts that fully dissociate. The conversation also touches on the relevance of molar conductivity and the implications of Ostwald's law of dilution for more complex scenarios.

PREREQUISITES
  • Understanding of molar concentration (c=n/V)
  • Familiarity with dissociation constants and their applications
  • Knowledge of Ostwald's law of dilution
  • Basic principles of electrical conductivity and ion movement
NEXT STEPS
  • Research the application of Ostwald's law of dilution in various chemical contexts
  • Explore Kohlrausch's law and its implications for electrical conductivity in solutions
  • Study the relationship between salinity and electrical conductivity in aqueous solutions
  • Investigate the concept of molar conductivity and its limitations in practical scenarios
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Chemistry students, educators, and professionals involved in analytical chemistry, particularly those focusing on solution chemistry and ionic dissociation.

H Smith 94
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Is there a formula to theoretically determine the number of moles of each ion present when a particular concentration of salt is dissociated in water?

I remember from A-level (high school) chemistry that concepts such as the dissociation constant exist but I'm struggling to apply them to concentration.

I am currently looking at the molar conductivity.
 
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Single formula? No. Theory that allows calculation of equilibrium concentrations? Yes.

Or do you mean just a simple case with something that fully dissociates? Then it is not even a formula, it just a direct application of the concentration definition, c=n/V.
 
Hi Borek, thank you for your quick response!

Borek said:
Single formula? No. Theory that allows calculation of equilibrium concentrations? Yes.

That sounds interesting and potentially useful. I'll look it up. Could you shed any light on anything you think may be useful?

Borek said:
Or do you mean just a simple case with something that fully dissociates? Then it is not even a formula, it just a direct application of the concentration definition, c=n/V.

So could I assume that NaCl dissociates perfectly in water, resulting in equal concentrations of Na+ and Cl-? Because that would make everything so much nicer. :biggrin:
 
H Smith 94 said:
That sounds interesting and potentially useful. I'll look it up. Could you shed any light on anything you think may be useful?

Check these pages:

http://www.chembuddy.com/?left=pH-calculation&right=general-pH-calculation

http://www.chembuddy.com/?left=pH-calculation&right=toc

While this is about pH calculation, the ideas behind are the same no matter what ions/species are involved.

H Smith 94 said:
So could I assume that NaCl dissociates perfectly in water, resulting in equal concentrations of Na+ and Cl-? Because that would make everything so much nicer.

For NaCl (and HS level) you can make such an assumption. At the undergraduate level you will be told it is not that simple, at the graduate level you will find details are a nightmare.
 
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Hi everyone, thank you for your help so far!

Does anyone know how the electrical conductivity ##\sigma## (conversely, resistivity ##\rho##) depends on salinity ##S## -- or more specifically, on the movement of dissolved ions in an electric field? I know they're in some way proportional but cannot find how!
 
Google Kohlrausch law.
 
Borek said:
Google Kohlrausch law.
Thank you! Yes, this is a very useful model. I've tried using it previously but found it limited by its semi-empirical nature.

I actually posted a question on this forum about it (which I completely forgot about until just now, oops!) If you wouldn't mind, perhaps you could look at my calculations on that post to see if the assumptions made make chemical sense. :biggrin:

I have no idea why I posted that in the Atomic, Solid State & Comp. forum, no wonder it got no answer!
 

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