Determining Number of Maxima: 2 Slits & 500 nm Light

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Homework Help Overview

The discussion revolves around a problem in wave optics, specifically concerning the interference pattern produced by two slits when illuminated by light of a specific wavelength. The original poster attempts to determine the number of maxima within a given angular range based on the parameters provided.

Discussion Character

  • Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster applies the formula for interference maxima and calculates a non-integer value for the number of maxima, prompting questions about the validity of their result. Some participants question the interpretation of the result, specifically regarding the need for whole numbers in counting maxima.

Discussion Status

The discussion is active, with participants engaging in clarifying the nature of maxima counts. A participant has pointed out the necessity for the number of maxima to be a whole number, which may guide the original poster to reconsider their calculations.

Contextual Notes

The original poster expresses uncertainty about the correctness of their calculation and the potential for error in the textbook reference, indicating a need for further verification of assumptions or interpretations of the problem.

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Homework Statement


Two slits are separated by 0.260 mm. A beam of 500 nm light strikes the slits, producing an interference pattern. Determine the number of maxima observed in the angular range -31.0° < θ < +31.0°.


Homework Equations


i used dsinθ = m(lambda)


The Attempt at a Solution


i used the formula above and got
(.26 x 10^-3)sin(31) = m (500 x 10^-9)

i got m as 267.82, but since there are 267.82 maxima to the right, and 267.82 to the left and one at m=0, that makes for a total number of 536.64 maxima

?
 
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i need to know what if i did anything wrong, or if the book is wrong
 
Hello hodgepodge.The number of maxima must be a whole number eg you may get 267 maxima on one side but not 267.82.
 
werd, thanks
 

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