Determining Number of Maxima: 2 Slits & 500 nm Light

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SUMMARY

The discussion focuses on calculating the number of maxima produced by a double-slit interference pattern when a beam of 500 nm light strikes slits separated by 0.260 mm. The formula used is dsinθ = mλ, leading to a calculated value of m as 267.82. However, since the number of maxima must be a whole number, the correct interpretation results in 267 maxima on each side of the central maximum, totaling 535 maxima, not 536.64 as initially stated.

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Homework Statement


Two slits are separated by 0.260 mm. A beam of 500 nm light strikes the slits, producing an interference pattern. Determine the number of maxima observed in the angular range -31.0° < θ < +31.0°.


Homework Equations


i used dsinθ = m(lambda)


The Attempt at a Solution


i used the formula above and got
(.26 x 10^-3)sin(31) = m (500 x 10^-9)

i got m as 267.82, but since there are 267.82 maxima to the right, and 267.82 to the left and one at m=0, that makes for a total number of 536.64 maxima

?
 
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i need to know what if i did anything wrong, or if the book is wrong
 
Hello hodgepodge.The number of maxima must be a whole number eg you may get 267 maxima on one side but not 267.82.
 
werd, thanks
 

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