Determining probability using combinations/permutations (i think)

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SUMMARY

This discussion focuses on calculating probabilities using combinations and permutations in a scenario involving a student facing an exam with 30 questions, of which 10 will be selected. The student knows how to solve 25 out of the 30 questions. For part (a), the probability of answering all 10 questions correctly is calculated as 0.1087, derived from the formula 25 choose 10 divided by 30 choose 10. For part (b), the approach involves calculating the probabilities of getting at least 8 questions right by considering the combinations of correct and incorrect answers.

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Homework Statement


a student has an exam, the teacher gives 30 questions and 10 of the 30 will be on the final exam. if the student knows how to solve 25 of the 30, what is:
a) the probability he will get perfect
b) the probability he will get at least 8 questions right


Homework Equations


permutations and combinations


The Attempt at a Solution


for part a i have:
sample space= 30Choose10= 30045015
to get all 10 questions right, the 10 questions on the exam must be within the 25 he knows how to do- 25choose10= 3268760. to find the probability i did: 3268760/30045015= 0.1087.
i don't think this is right because it seems too low and since he knows most of the questions i would expect the probability to be higher.

for part b: i use the same sample space of 30choose10, but I am stuck on the "at least 8 questions right part"

any help for this would be appreciated
 
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You've got the first one right. Yeah, it seems kind of low, but then he only knows how to solve 'most of them'. And he has to get 10 right in a row. It's not that unreasonable. For the second one what's the probability he gets 9 questions right and 1 wrong and what's the probability he get 8 right and 2 wrong. Then add those two to the probability from the first question.
 

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