# Determining the cartesian equations

1. Jul 25, 2010

### shawns

1. The problem statement, all variables and given/known data

determine the cartesian equation of the plane that contains the following lines:
L1: r= (4,4,5) + t(5,-4,6)
L2: r= (4,4,5) + s(2,-3,-4)

2. Relevant equations

I kno i'm supposed to use the equation Ax + By + Cz + D. but i don't know how to use it with this type of problem

3. The attempt at a solution

Don't understand it at all :S

2. Jul 25, 2010

### jegues

Two lines can be contained in a plane if and only if,

a) The lines are parallel, or
b) The lines intersect

Hint: The direction vectors of each line should indicate whether they are parallel or not

Does that help?

Last edited: Jul 25, 2010
3. Jul 25, 2010

### Staff: Mentor

Ax + By + Cz + D is NOT an equation. The equation you're thinking of is Ax + By + Cz + D = 0.
You are given a point in the plane and two vectors that are in the plane. You need to work with the two vectors to find a third vector that is perpendicular to the plane.