The discussion focuses on determining the Cartesian equation of a plane containing two lines, L1 and L2, defined by their parametric equations. The lines are given as L1: r = (4,4,5) + t(5,-4,6) and L2: r = (4,4,5) + s(2,-3,-4). To find the plane's equation, users must utilize the formula Ax + By + Cz + D = 0, where the coefficients A, B, and C represent the components of a normal vector derived from the cross product of the direction vectors of the two lines. Understanding the relationship between the lines and their direction vectors is crucial for solving the problem.
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Ax + By + Cz + D is NOT an equation. The equation you're thinking of is Ax + By + Cz + D = 0.shawns said:Homework Statement
determine the cartesian equation of the plane that contains the following lines:
L1: r= (4,4,5) + t(5,-4,6)
L2: r= (4,4,5) + s(2,-3,-4)
Homework Equations
I kno I'm supposed to use the equation Ax + By + Cz + D. but i don't know how to use it with this type of problem
shawns said:The Attempt at a Solution
Don't understand it at all :S