Determining the irrationality of a quotient

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The quotient (7)^(1/2)/(15)^(1/3) is irrational. The term (7)^(1/2) is established as irrational due to its prime nature. The term (15)^(1/3) can be decomposed into (5)^(1/3) * (3)^(1/3), both of which are also irrational. By assuming the quotient is rational and raising both sides to the sixth power, one can apply prime divisibility arguments to reach a contradiction, thereby proving the irrationality of the entire expression.

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Determine whether (7)1/2/(15)1/3 is either rational or irrational and prove your answer is correct.

So I know that (7)1/2 is irrational from previous theorems since it is a prime, I also split up (15)1/3 into (5)1/3 times (3)1/3. I previously had shown that (5)1/3 is also irrational. Doing this question I showed that (3)1/3 is irrational by the uniqueness of prime factorization.

But my problem lies in showing that this whole quotient is irrational. I don't know where to start. Maybe assume that the quotient is rational and obtain a contradiction? If so how could I start it?
 
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trap101 said:
Determine whether (7)1/2/(15)1/3 is either rational or irrational and prove your answer is correct.

So I know that (7)1/2 is irrational from previous theorems since it is a prime, I also split up (15)1/3 into (5)1/3 times (3)1/3. I previously had shown that (5)1/3 is also irrational. Doing this question I showed that (3)1/3 is irrational by the uniqueness of prime factorization.

But my problem lies in showing that this whole quotient is irrational. I don't know where to start. Maybe assume that the quotient is rational and obtain a contradiction? If so how could I start it?

Yes, assume it's equal to a rational and assume its in lowest terms. Then take the sixth power of both sides. Then make the usual sort of arguments about prime divisibility.
 

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