Determining the minimum velocity when given height and length

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The discussion focuses on calculating the minimum velocity required for a jump given the height and length of the jump. The user correctly identifies the height as 'h' and the length of the jump as 's', incorporating gravity into their calculations. They derive the time of flight using the formula t = √2h/g, resulting in approximately 0.62 seconds, and then calculate the velocity as v = s/t, yielding 19.35 m/s. The user expresses uncertainty about whether they should be considering initial velocity (Vo) and how the horizontal plane affects the problem. Responses confirm that their method is correct and that the horizontal component of velocity remains constant.
arhzz
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Homework Statement
A stunt driver wants to jump with his car over several cars parked next to each other (a = 12m). He starts from a horizontal plane which is b = 1,9m above the cars.At what minimum speed does he have to jump off, to make the jump
Relevant Equations
t = √2h/g
Now I've tried looking at the problem like this. Considering that a is the length off the vehicles that he is trying to jump over I would consider that to be s. The plane from which he starts (b) should be the h.

So considering that he is jumping from a horizontal plane, gravity should also play a factor so we put in the g constant.After doing this what I though would be a good idea is to figure out when he would land, meaning how long would he fly.For that I used this formula

t = √2h/g

That should be t = 0,62s

Now what I did was try to find the velocity using this formula

v = s/t

I've gotten the result of 19,35 m/s.

Now the part that is bugging me is am I looking at the problem the correct way? I've given it some tought and I'm not so sure that the velocity I am getting is the right one, should I be looking for Vo? Also the fact that horizontal plane is explicity said also brings a few questions. We haven't really covered that in our class but it is in the script. Should I be looking the problem that way?

Thank you for your help.
 
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Your method and result are fine. The horizontal component of velocity does not change.
 
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haruspex said:
Your method and result are fine. The horizontal component of velocity does not change.
Thank you for your answer!
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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