Determining the normalization constant C

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To determine the normalization constant C for the distribution function F(x) = Cexp(-ax), it is essential to ensure that the integral of the probability density function f(z) over its entire range equals 1. The average value <z> can be calculated using the formula <z> = ∫ z f(z) dz / ∫ f(z) dz, but this approach is only valid if f(z) is not normalized. The correct method involves finding C such that the integral ∫ f(z) dz = 1 holds true. Ultimately, the normalization process confirms that the distribution function is properly scaled.
SirCrayon
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Homework Statement


Consider the distribution function F(x) = Cexp(-ax)

Find the normalization constant C


Homework Equations



The Attempt at a Solution



This is more clarification since this is not actually a homework problem but was in my profs notes. He started with the distribution function above and said we were to determine C.

He then gave us the average equation below:
<z> = ∫ z f(z) dz / ∫ f(z) dz

Which in this case would be xexp(-ax) / exp(-ax)

I am a little confused as to how you are able to determine the constant C if you determine the average of the system/distribution.
 
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If a distribution is normalized, that means
$$\int f(z)\,dz = 1,$$ where the integral is taken over the entire range of z. In this case, the formula for the average simplifies to
$$\langle z \rangle = \int z f(z)\,dz.$$ The formula your professor gave works for the case where f(z) isn't normalized.

To normalize the F(x) you've been given, you want to find the value of C such that the first integral holds.
 

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