Determining the path of a particle in a field

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SUMMARY

To determine the path of a particle in a vector field, integration of Newton's equations of motion is essential. A simple force field can be represented as F = xi + yj, where the components lead to differential equations for position over time. For a potential energy field defined by x + y, the force vector is the negative gradient, resulting in equations of motion that can be integrated to find the particle's trajectory. Understanding these principles is crucial for accurately modeling particle dynamics in various fields.

PREREQUISITES
  • Understanding of vector fields and their components
  • Knowledge of Newton's equations of motion
  • Familiarity with integration techniques in calculus
  • Concept of potential energy and its relation to force
NEXT STEPS
  • Study vector field representation and characteristics
  • Learn about Newton's laws of motion and their applications
  • Explore integration methods for solving differential equations
  • Investigate the relationship between potential energy fields and force vectors
USEFUL FOR

Students and professionals in physics, engineers working with particle dynamics, and anyone interested in the mathematical modeling of forces and motion in fields.

fishspawned
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Homework Statement
using integration to determine paths of travel
Relevant Equations
F(x,y) = x+y [for example]
This is not a specific homework question, but more of a general query.

If provided with a simple vector field indicating forces (for example, an electrical field), can you use integration to determine the path of a particle placed in that field, if also provided with some initial conditions? Let's say this is a simple 2D plane where the field follows something fairly simple, like F(x,y) = x+ y. Can this be done? Can anyone point me in the right direction to learn more about this?

Consider this as an attempt to change a grid of vectors into a set of field lines that, at the same time, show the path of a set particles within that field
 
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A vector field has components. Your F does not.
Apart from that, the answer to your question is yes: you integrate Newton's equations of motion to get the path.
(That's how the SUVAT equations come about).
 
Your field, F= x+ y, is NOT a "vector field" because x+ y is not a vector!

If you had something like F= xi+ yj then, since Force= mass* acceleration, the acceleration would be \frac{d^2x}{dt^2}= x and \frac{d^2y}{dt^2}= y. The "characteristic equation" of both is r^2= 1 and So that x(t)= Ae^t+ Be^{-t} and y(t)= Ce^t+ De^{-t}.

Another possibility is that F is not a force vector but a potential energy field. In that case, the force is given by the negative of the gradient of the potential energy field. With potential energy x+ y, the force vector is -i- j. Then \frac{d^2x}{dt^2}= -1and \frac{d^2y}{dt^2}= -1so that, integrating twice, x(t)= -\frac{t^2}{2}+ At+ B and y(t)= -\frac{t^2}{2}+ Ct+ D.
 

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