Determining the set of points at which the function is continuous.

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SUMMARY

The function F(x,y) = arctan(x + √y is continuous at points where the expression inside the arctan is defined. Specifically, the square root function √y requires y to be non-negative (y ≥ 0). Thus, the set of points at which F is continuous is defined by the condition that y must be greater than or equal to zero, allowing for all real values of x. The discussion highlights the importance of understanding the domain of the function and the implications of continuity in multivariable calculus.

PREREQUISITES
  • Understanding of multivariable calculus concepts
  • Familiarity with the arctangent function and its properties
  • Knowledge of the square root function and its domain
  • Basic skills in applying the chain rule for differentiation
NEXT STEPS
  • Study the properties of the arctan function and its continuity
  • Learn about the implications of domain restrictions in multivariable functions
  • Explore the chain rule in the context of multivariable calculus
  • Investigate the relationship between continuity and differentiability in functions of multiple variables
USEFUL FOR

Students studying calculus, particularly those focusing on multivariable functions, as well as educators looking for examples of continuity in mathematical analysis.

SneakyG
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Homework Statement


Determine the set of points at which the function is continuous.
F(x,y) = arctan(x + √y)

Homework Equations


Perhaps the chain rule?


The Attempt at a Solution


I derived it, but the solution in the back of the book is nothing like what I expected. It involves e and other trig functions.
 
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SneakyG said:

Homework Statement


Determine the set of points at which the function is continuous.
F(x,y) = arctan(x + √y)

Homework Equations


Perhaps the chain rule?


The Attempt at a Solution


I derived it, but the solution in the back of the book is nothing like what I expected. It involves e and other trig functions.

So show us what you did.
 

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