Determining total amplitude of out of phase waves

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SUMMARY

The total amplitude of two sinusoidal waves with amplitudes of 3 cm and 4 cm, differing in phase by π/2 radians, is definitively calculated to be 5 cm. This is derived using the formula A = 3 sin X + 4 cos X, which simplifies to A = 5 (3/5 sin X + 4/5 cos X). By defining φ as tan⁻¹(4/3), the resultant amplitude can be expressed as A = 5 sin(X + φ). This method utilizes complex numbers for a clear solution.

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Gza
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I understand there is a way to solve the problem with complex numbers, but am at a loss as to how:

Determine the amplitude of the resultant motion when two sinusoidal motions having the same frequency and traveling in the same direction are combined, if their amplitudes are 3 cm and 4 cm and they differ in phase by pi/2 radians.
 
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Gza said:
I understand there is a way to solve the problem with complex numbers, but am at a loss as to how:

Determine the amplitude of the resultant motion when two sinusoidal motions having the same frequency and traveling in the same direction are combined, if their amplitudes are 3 cm and 4 cm and they differ in phase by pi/2 radians.

The amplitude will be 5!

Basically

A = 3 \sin X + 4 \cos X = 5 \left ( \frac {3}{5} \sin X + \frac {4}{5} \cos X \right)

where X is the time/space phase. Now just define \phi = \tan^{-1} \frac {4}{3} so that

A = 5 \sin \left( X+\phi \right)
 
You are a busy man tide! Thanks for the help. :smile:
 

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