Determining wind velocity vector.

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The discussion revolves around calculating the wind velocity vector affecting a light plane flying south at 185 km/h. After one hour, the plane has only traveled 136 km and is heading Southeast at a 45-degree angle, indicating a deviation from its intended path. Participants express uncertainty about using vector components and trigonometric methods to solve the problem. There is mention of the need to consider the relationship between the plane's velocity and the wind's influence, suggesting a vector addition approach. The challenge lies in accurately determining the wind's effect on the plane's trajectory.
Jonathan Teas
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Homework Statement


A light plane is headed due south with a speed of 185km/h "relative to still air". After 1.0hr, the pilot notices that they have only covered 136km. And that their direction is Southeast 45 degrees. What is the wind velocity?


Homework Equations


Im guessing you have to use i, j substitution, but I am just not sure of how or what you would do.



The Attempt at a Solution


I drew it out, and tried solving it trigonometricly...Failed. Tried to look at it the same way as problems with someone swimming and a current pushing them away from their destination point, but I just couldn't figure it out.
 
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Jonathan Teas said:

Homework Statement


A light plane is headed due south with a speed of 185km/h "relative to still air". After 1.0hr, the pilot notices that they have only covered 136km. And that their direction is Southeast 45 degrees. What is the wind velocity?


Homework Equations


Im guessing you have to use i, j substitution, but I am just not sure of how or what you would do.



The Attempt at a Solution


I drew it out, and tried solving it trigonometricly...Failed. Tried to look at it the same way as problems with someone swimming and a current pushing them away from their destination point, but I just couldn't figure it out.

\vec{A}=\vec{B} + \vec{C}

Vector B and C not necessarily orthogonal as in river crossing.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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