Determinism, Stokes' Theorem and Relativity

Click For Summary

Discussion Overview

The discussion revolves around the compatibility of determinism, Stokes' Theorem, and Relativity Theory, exploring the implications of these concepts in the context of spacetime physics and boundary value problems. Participants examine the nature of determinism in relation to predictions based on initial conditions and boundary conditions in physical theories.

Discussion Character

  • Debate/contested
  • Technical explanation
  • Mathematical reasoning

Main Points Raised

  • Some participants argue that determinism implies that knowing the state of a spacelike hypersurface allows predictions about future states, while others challenge this by emphasizing the necessity of boundary conditions.
  • One participant discusses the Kelvin-Stokes theorem and its implications for the relationship between values at different times, suggesting it complicates the notion of determinism.
  • Another participant highlights the distinction between different types of boundary value problems, noting that for second-order equations, both the field and its normal derivative must be specified on the initial surface.
  • There is a discussion about the physical implications of boundary conditions, with one participant noting that a photon could disrupt predictions unless boundary conditions are properly specified.
  • Concerns are raised about the measurability of certain fields, questioning whether charge density can be measured independently of electric or magnetic fields, and how this relates to the determination of electromagnetic phenomena.

Areas of Agreement / Disagreement

Participants express differing views on the compatibility of determinism with Stokes' Theorem and Relativity Theory, with no consensus reached. The necessity of boundary conditions in making predictions is acknowledged, but the implications of this requirement remain contested.

Contextual Notes

Participants note limitations in the discussion, including the dependence on definitions of measurable quantities and the potential non-physical nature of certain textbook problems involving boundary conditions.

Phrak
Messages
4,266
Reaction score
7
I don't think these three: {Determinism, Stokes' Theorem, Relativity Theory}, are compatible.

The notion of determinism, as applied to spacetime physics, means that if we know everything on an R3 spacelike hypersurface at time ta, we can predict what will be will be the state of things on an R3 spacelike hypersurface at some future time, tc.

The Kelvin-Stokes theorem,

[tex]\int_{t_a}^{t_c}f(t')dt' = F(t_c)-F(t_a)[/tex]​

seems to say something else:-

It tells me that what I see at time tb, where ta<tb<tc, is defined by the events at both ta and tc up to a constant of integration.
 
Last edited:
Physics news on Phys.org
There are different kinds of boundary value problems. Typically you specify one value everywhere on the boundary, and the field inside is determined. For a second order field equation like the wave equation, the "value" can either be the field Φ itself or its normal derivative ∇Φ. With an appropriate choice of the surface of integration, the surface integral boils down to an integration over all space at t = ta and t=tb. As you point out this is unphysical, since it makes Φ appear to depend on its value at some future time. So you use instead Cauchy conditions, which specify both Φ and ∇Φ on just the initial surface t = ta.

The situation is clearer for first order equations, which is why Dirac sought a set of first order equations to describe electrons. For a first-order matrix equation Φt = M Φ, you just need to specify Φ at t = ta.
 
Bill_K said:
As you point out this is unphysical, since it makes Φ appear to depend on its value at some future time. So you use instead Cauchy conditions, which specify both Φ and ∇Φ on just the initial surface t = ta.

I didn't point out that it was nonphysical but take serious consideration. Consider ∇Φ to be the measurable quantity and Φ to be a gauge field, Φ <-- Φ' = Φ + dφ.
 
Phrak said:
I don't think these three: {Determinism, Stokes' Theorem, Relativity Theory}, are compatible.

The notion of determinism, as applied to spacetime physics, means that if we know everything on an R3 spacelike hypersurface at time ta, we can predict what will be will be the state of things on an R3 spacelike hypersurface at some future time, tc.

Actually, this isn't quite the case. As the other posters mentioned, you need to know not only everything on the space-like hypersurface at some time, you also need the boundary conditions, even in classical mechanics.

For example, a photon or "light packet" could come in "from infinity" and upset things, unless one specifies the boundary conditions so this doesn't happen.

There is extensive discussion in Wald, "General Relativity", of the initial value formulation of GR, if you have the textbook. Chapter 10. So if you're trying to argue that GR doesn't have a well posed initial value formulation, you'll have to show where Wald went wrong...
 
pervect said:
Actually, this isn't quite the case. As the other posters mentioned, you need to know not only everything on the space-like hypersurface at some time, you also need the boundary conditions, even in classical mechanics.

You can't get away with anything around here. I was attempting to state the issue in the simplest possible manner, but not too simple. I guess I didn't.

Of course, we need all the entire R^3 hypersurface encompassing a 4-volume, to be precise. This shouldn't distract from the question.
 
In attempting to decern which fields are measurable and which are not I've asked, "Can charge density be measured without electric or magnetic fields?" Also, "Can electric and magnetic fields be measured without charge?" The answer seems to be no.

Given this (and please correct me if I am wrong) only the products of second and third derivatives of the 4-vector electromagnetic potential are at our disposal to determine the current, past, and future values of electromagnetic phenomena.

Bill_K, you've given much food for thought. In the above, I mean we can set up many textbook problems with bounary conditions in ∇Φ and Φ, where Φ is some tensor, but not all of these field values are really accessible by experimentation, and so these textbook execises are somewhat constrived and nonphysical.
 
Last edited:

Similar threads

  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 76 ·
3
Replies
76
Views
4K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 75 ·
3
Replies
75
Views
7K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 4 ·
Replies
4
Views
1K
  • · Replies 78 ·
3
Replies
78
Views
7K
  • · Replies 3 ·
Replies
3
Views
2K