Diagonalizing and expressing as A^k

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SUMMARY

The discussion focuses on diagonalizing the matrix A=\left(\begin{array}{cc}11 & 6\\-12 & -6\end{array}\right) and expressing A^k as an explicit 2x2 matrix. The user successfully diagonalized A, obtaining P=\left(\begin{array}{cc}-3 & -2\\4 & 3\end{array}\right) and D=\left(\begin{array}{cc}3 & 0\\0 & 2\end{array}\right). Using the formula A^k=PD^kP^{-1}, they derived A^k=\left(\begin{array}{cc}9*3^k-8*2^k & 6*3^k-6*2^k\\-12*3^k+12*2^k & -8*3^k+9*2^k\end{array}\right). The solution is confirmed as correct and satisfactory.

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Students studying linear algebra, mathematicians focusing on matrix theory, and anyone interested in applying diagonalization techniques to solve matrix equations.

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Homework Statement


Let [tex]A=\left(\begin{array}{cc}11 & 6\\-12 & -6\end{array}\right)[/tex] and let k be a positive integer. By diagonalizing A, express Ak as an explicit 2x2 matrix in terms of k. Your answer should take the form [tex]A=\left(\begin{array}{cc}f_1 (k) & f_2 (k)\\f_3 (k) & f_4 (k)\end{array}\right)[/tex]

Homework Equations


P-1AP=D and Ak=PDkP-1.

The Attempt at a Solution


I don't have a problem diagonalizing, I have a problem with expressing it in terms of functions (at least I think). I diagonalized normally and got [tex]P=\left(\begin{array}{cc}-3 & -2\\4 & 3\end{array}\right)[/tex] and [tex]D=\left(\begin{array}{cc}3 & 0\\0 & 2\end{array}\right)[/tex] After using the second formula above, I get [tex]A^k=\left(\begin{array}{cc}9*3^k-8*2^k & 6*3^k-6*2^k\\-12*3^k+12*2^k & -8*3^k+9*2^k\end{array}\right)[/tex] I am just not sure if this is "good enough" or even right? Is there some way I can combine this? Just want to double check my answer basically :smile:
 
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This looks good! :smile:
 
Thank you :smile:
 

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