Diameter of copper wire to have same resistance as equal length aluminum wire

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SUMMARY

The diameter of a copper wire required to match the resistance of an equal length aluminum wire with a diameter of 3.94 mm is calculated using the formula R = ρL/A. Given the resistivity values of copper (1.72x10-8 Ωm) and aluminum (2.82x10-8 Ωm), the correct diameter for the copper wire is approximately 3.08 mm. The initial calculation of 55.31 mm was incorrect due to an error in determining the cross-sectional area of the aluminum wire. The correct area for the aluminum wire is 3.88x10-6 m2, leading to the accurate copper wire diameter.

PREREQUISITES
  • Understanding of electrical resistance and resistivity
  • Familiarity with the formula R = ρL/A
  • Knowledge of cross-sectional area calculations for circular wires
  • Basic concepts of material properties, specifically resistivity of copper and aluminum
NEXT STEPS
  • Learn about the resistivity of different materials and how it affects electrical resistance
  • Explore the impact of wire diameter on resistance in electrical circuits
  • Study the differences between annealed and plain copper in terms of resistivity
  • Investigate practical applications of resistance calculations in electrical engineering
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Electrical engineers, physics students, and anyone involved in designing or analyzing electrical circuits that require precise resistance calculations.

Northbysouth
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Homework Statement


What diameter must a copper wire have if its resistance is to be the same as that of an equal length of aluminum wire with diameter 3.94mm?

Give your answer in mm

Homework Equations



R = ρL/A

where A is the cross sectional area, L is the length and ρ resistance of the material

ρCopper = 1.72x10-8 Ωm
ρAluminum = 2.82x10-8 Ωm

The Attempt at a Solution



So I knew that Rcopper = RAluminum

(1.72x10-8Ωm)(L)/Acopper = (2.82x10-8Ωm)(L)/(0.00394m)

A = 0.00240 m
A = πr2

r = 0.027657 m

diameter = 55.31499 mm

But the system says its wrong and I don't see where I've gone wrong.
 
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Northbysouth said:

Homework Statement


What diameter must a copper wire have if its resistance is to be the same as that of an equal length of aluminum wire with diameter 3.94mm?

Give your answer in mm

Homework Equations



R = ρL/A

where A is the cross sectional area, L is the length and ρ resistance of the material

ρCopper = 1.72x10-8 Ωm
ρAluminum = 2.82x10-8 Ωm

The Attempt at a Solution



So I knew that Rcopper = RAluminum

(1.72x10-8Ωm)(L)/Acopper = (2.82x10-8Ωm)(L)/(0.00394m)
Start with what I've highlighted above in red.

  • What are units for area: meters or square meters?
  • Before calculating the cross section area of the copper wire, first ask, what is the cross sectional area of the aluminum wire? :wink:

[Edit: On a much lesser note, and I'm not sure if this matters, according to some sources I've looked at on the Internet, 1.72x10-8 Ωm is the resistivity of annealed copper. Plain old copper has a very similar resistivity, but slightly different. Use whatever your course material advises. And again, the difference is small and I'm not sure if copper vs. annealed copper matters.]
 
Last edited:
I see what you're saying.

The cross section area od aluminum is π(0.00197m)2

3.8809x10-6 m2

Then solving for the cross sectional area of copper I get

Acopper = 7.4364x10-6 m2

rcopper wire = sqrt(7.4363x102/π)

Diameter of copper wire = 2r = 3.077059 mm

Thanks for your help
 

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