1. A fountain sends a stream of water straight up into the air to a maximum height of 4.23 m. The effective area of the pipe feeding the fountain is 5.38 x 10^-4 m^2. Neglecting air resistance and any viscous effects, determine how many gallons per minute are being used by the fountain. (1 gal = 3.79 x 10^-3 m^3) 2. Relevant equations F = (mv^2)/r F = P * A P = density * g * h m = density*(Ah) 3. The attempt at a solution P= 1.013x10^5 * pgh P= 1000*9.8*4.23 + 1.013x10^5 P= 142754 Pa PA = F PA = (mv^2)/r r = (Area/pi)^(1/2) r= .013086 m mass = 1000 * area * 4.23 mass = 2.27574 kg 142754 Pa * (5.38 *10^-4 m^2) = (2.27574 kg * v^2)/.013086 m v = .66455 (m/s multiply by area .66455 * (5.38 * 10^-4) = .0001926 m^3/s divide v by 3.79 * 10^-3 m^3, then multiply by 60 seconds 5.66 gal/min this is so obviously wrong, but i've tried this prob beyond five times already and am at wits end... can anyone steer me in the right direction? thankkkks!