Did I do this physics problem right?

[zeromodz]

Its not for homework, I just want to make sure I can do this.

What is the value of the coefficient of friction between the box and the floor?
A man pushes a box with a mass of 10kg at a constant velocity across the floor. he pushes with a constant force of 25N. What is the coefficient of friction value?


F = ukN
uk = F / N
uk = (25) / ((10)(9.8))
uk = 0.25

 

[LostConjugate]

You will need to know at what rate the box accelerates at in order to find the friction co-efficient.

 

[Mu naught]

You will need to know at what rate the box accelerates at in order to find the friction co-efficient.

Not for this problem. If the velocity is constant, which the problem stated, then the net force is zero.

So mgcosθμ = 25

98μ = 25

μ = .2551...

so yes you're correct.