Did I Make a Mistake in my Coordinates? Help Needed!

  • Context: Undergrad 
  • Thread starter Thread starter Shafia Zahin
  • Start date Start date
  • Tags Tags
    Confusion Coordinates
Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
4 replies · 1K views
Shafia Zahin
Messages
31
Reaction score
1
In the attached pic,it is shown that the coordinates of point B are (a cos theta, a sin theta) ,but shouldn't it be (-a cos theta,a sin theta)? Can anybody please help?
 

Attachments

  • IMG_20170614_142305.jpg
    IMG_20170614_142305.jpg
    55 KB · Views: 555
Mathematics news on Phys.org
No there is nothing wrong with the labeling of the coordinates in the diagram. Recall that ##\cos \theta## is negative for ##\pi/2 < \theta < 3\pi/2## (or what you may know as the second and third quadrants).
 
  • Like
Likes   Reactions: WWGD
Fightfish said:
No there is nothing wrong with the labeling of the coordinates in the diagram. Recall that ##\cos \theta## is negative for ##\pi/2 < \theta < 3\pi/2## (or what you may know as the second and third quadrants).
But didn't it come like this?(see the attachment)
 

Attachments

  • IMG_20170614_144504.jpg
    IMG_20170614_144504.jpg
    38.2 KB · Views: 490
When you did the triangle construction in your diagram, you treated ##x## there as a length, which only takes on positive values, but ignored its position relative to where the origin was defined. So, the x-coordinate of the point should in fact be the negative of the ##x## in your derivation.
 
Fightfish said:
When you did the triangle construction in your diagram, you treated ##x## there as a length, which only takes on positive values, but ignored its position relative to where the origin was defined. So, the x-coordinate of the point should in fact be the negative of the ##x## in your derivation.
Oh,now I got it,thank you so much:smile: