Dielectric-Dielectric Boundary Conditions

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SUMMARY

The discussion centers on the dielectric-dielectric boundary conditions, specifically addressing the confusion regarding the electric field components at the boundary. The equation presented, \(\oint_{C} \vec{E} \cdot \vec{dl} = E_{1t}\Delta l - E_{2t}\Delta l = 0\), illustrates that the net electric field \(E_{net}\) at the boundary is derived from the difference between the tangential components of the electric fields in the two media, \(E_{net} = E_{1t} - E_{2t}\). The participant clarifies that the direction of \(\Delta l\) is crucial for understanding the signs of the electric field components. This highlights the importance of vector direction in boundary condition problems.

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jegues
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Homework Statement



No problem, I just have a confusion about a certain concept.

Homework Equations





The Attempt at a Solution



I'm confused as to how they draw the result,

[tex]\oint_{C} \vec{E} \cdot \vec{dl} = E_{1t}\Delta l - E_{2t}\Delta l = 0[/tex]

You don't really need to do the integration since,

[tex]\Delta l[/tex]

is so small. Thus the result must be,

[tex]E_{net} \Delta l[/tex]

But why is it such that,

[tex]E_{net} = E_{1t} - E_{2t}?[/tex]

It looks as though they are pointing in the same direction in the figure.

Can someone explain? Am I mixing some things up?

Thanks again!
 

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[itex]\vec{\Delta l\phantom{ll}}[/itex] is to the right in one medium, to the left in the other.
 
SammyS said:
[itex]\vec{\Delta l\phantom{ll}}[/itex] is to the right in one medium, to the left in the other.

Doh.

Thank you.
 

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