Baluncore said:
I would like to buy an argument. Consider a resonant half-wave dipole in free space. Model it as an inductive wire in the middle with capacitance between the ends. The current at the centre will be a maximum as the voltage between the ends passes zero. V and I are therefore in quadrature. But since the intrinsic impedance of free space is real, with a value of about 377 ohms, an EM wave in space has the E and H components in phase.
What gives?
The current in the element seems to generate the magnetic component. That H then creates the perpendicular E electric field which permits the wave to proceed through space. It seems the voltage on the dipole is irrelevant.
My take on this is based on experiments which I undertook as an amateur scientist. There are some imperfections still in understanding. The inductance and capacitance are not part of the radiation mechanism. They store reactive energy and create induction fields which are in quadrature. At switch-on, these fields charge up over a few cycles and at switch-off they similarly decay. The L-C resonance makes it easy to drive a current into the antenna, only the Radiation Resistance being involved if losses are small.
The radiation is caused when the voltage at the feedpoint accelerates electrons in the wire. This causes the static fields of the electrons to be tilted, creating a transverse radiated E-field. When this electric wave passes a magnetic sensor, as a consequence of Relativity we see a magnetic field.
The acceleration also causes the electrons to have a velocity, and this equates to a current. The magnetic field of this current is initially indistinguishable from the B radiation, as it is in-phase and falls off with 1/r. However, at a distance of lambda/2 pi, it is found that this field begins to decay more rapidly, whereas the radiated B field continues outwards as radiation, falling with 1/r for ever.
The radiated E-field remains constant out to lambda/2pi, but retards in phase. It then falls with 1/r for ever. The induction E-field does not retard in phase with distance - I believe Hertz noticed this.
Very close to the feedpoint we see a local E-field caused by the feeder voltage. This voltage is equal to the volt drop in the Radiation Resistance, and may be equated to the transverse E-field generated by the accelerating electrons. The induction E-field from the dipole ends is strong near the ends but small near the equatorial plane of the antenna.
In a general case, if we bring probes near a radiating dipole, we see that the E-field initially increases at 6dB per octave of distance as we approach, but remains about constant from lambda/2 pi until very close to the antenna. Very close we see a 6dB increase due to the feeder voltage.
With a magnetic probe the field increases 6dB per octave all the way until we touch the centre of the antenna, so may be typically 20dB or so greater than the E-field when touching the conductor.
If we use a terminated dipole as a probe, the received power remains constant from lambda/2 pi until we physicaly touch the antenna. When we touch the antenna there is no jump in received power. Closer than lambda/2 pi the received power is always half the transmit power, so the path loss between two dipoles never falls below 3dB. This is because when they touch, they form one antenna and half the power is radiated and the other half delivered to the receiver.
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