mikeeey said:
I know that manifolds are topological spaces that locally look like euclidean spaces near each point of and open neighbourhood
The use of the word Euclidean space for R^n can be confusing. To say that a manifold looks locally like Euclidean space means that is it locally homeomorphic to R^n. There is no concept of geometry implicit in this definition. In Riemannian geometry, manifolds are topological spaces that are then given a geometry by adding a Riemannian metric. The topological Euclidean space becomes geometrically Euclidean when it is given the usual dot product metric. Then one can talk about angles and lengths and other geometric ideas. One can think of a metric as giving the space an idea of measurement.
And non-euclidean spaces are the curved spaces or simply don't match the 5th euclid's axiom
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It turns out that any topological manifold that is smooth can be given a Riemannian metric. In fact there are infinitely many possible inequivalent Riemannian metrics and each gives a different geometry to the manifold. For instance an egg and a sphere are both topological spheres but they have different metrics and different geometries.
On a manifold with a geometry, it is almost always not useful to think about whether Euclid's fifth postulate is satisfied or not. This is because there is no easy generalization of the idea of a plane. However, one can test whether a space has Euclidean geometry locally by checking whether the Pythagorean theorem holds for small right triangles or by checking whether the sum on the angles of a triangle is always 180 degrees. Other tests, ones that are often described in Physics, are to see whether the circumference of a small sphere is 2pi times its radius or to see whether the distance between line segments that start out parallel is constant when measured from different points. If a manifold passes the locally Euclidean geometry test at every point, then one gets a generalization of the idea of Euclidean geometry to manifolds that have a different topology than R^n. Examples of locally Euclidean surfaces are the flat torus and the flat Klein bottle.
So a manifold with a Riemannian geometry is not Euclidean if it fails the local Euclidean geometry test. In this case, the manifold has a non-zero Riemann curvature tensor so it is not unfair to say that it is a curved space. One needs to be careful here about what curved means though. For instance a cylinder made out of a piece of paper is not curved in this sense. Also, the Riemann curvature tensor is identically zero for a space that does satisfy the local Euclidean geometry test.
Sometimes the idea of geometry is restricted to manifolds that look the same everywhere. Just like Euclidean space which is geometrically uniform, other spaces can also be geometrically uniform. An inhabitant of such a space would not be able to tell where he is from the local geometry. For surfaces, a requirement for uniformity is constant Gauss curvature. Gauss curvature measures the extent to which a surface fails the local Euclidean geometry test. So an egg would not be such a uniformly curved space since it is more pointy at one end but a sphere would be. For constant negative curvature you can look up the pseudosphere for a nice picture.
It turns out that there is a second plane geometry, the one where there are infinitely many parallels rather than only one(so Euclid's 5'th Postulate does not hold) , and this space considered as a having a Riemannian geometry has constant negative Gauss curvature. So it is accurate to say that this non-Euclidean geometry is a curved space - where by curved you mean non-zero constant Gauss curvature. The usual Euclidean geometry in the plane is not called curved because its Gauss curvature is everywhere zero.
In addition to constant curvature, one may require that the manifold be "homogeneous" which means that there is an isometry (metric preserving homeomorphism) of the manifold into itself that maps any point into any other. For instance the sphere is homogeneous since any point can be rotated into any other. This is a stronger idea than any two locations on the manifold being geometrically indistinguishable. One can ,for instance, even find manifolds of zero curvature that have only finitely many isometries.