1. The problem statement, all variables and given/known data The alaskan pipeline has a capacity of 2.37*105m3/day of oil per day. Along most of the pipeline the radius is 60 cm. Find the pressure at a point where the pipe has a 35 cm radius. Take the pressure in the section with radius 60 cm to be 160 kPa and the density of oil to be 800kg/m3. Answer in units of kPA 2. Relevant equations .5 * rho * v12+ rho * g * y + p1 = .5 * rho * v22 + rho * g* y + p2 since y = 0, we end up with: .5 * rho * v12+ p1 = .5 * rho * v22 + p2 v2 = v1 ( A1 / A2) 3. The attempt at a solution v1 = 2.37x10^5 m^3/day = 2.743055556 m^3/sec A1 = 60^2*pi = 11309.73355 cm^2 A2 = 35^2 * pi = 3848.451001 cm^2 v2 = v1 * (A1/A2) p1-p2 (difference in pressure) = (.5)(rho)(v2^2) - (.5)(rho)(v1^2) substitute: = (.5)(rho) ((v1*A1/A2)^2) - (.5)(rho)(v1^2) = (.5)(rho)(v1^2) [(a1/a2)^2 - 1] plugging in: = (0.5)(800)(2.743055556)^2 (7.636401493) = 22983.59459 Pa = p1-p2 since we're given p1 = 160 kPa, converting the difference in pressure to kPa and subtracting yields 22.98359459 = 160 - p2 p2 = 137.0164054 kPa However, this is an in correct answer. Does anyone see where I'm making my mistake?