Differences between Raman stokes and fluorescence

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SUMMARY

The discussion clarifies the fundamental differences between Raman scattering and fluorescence. Fluorescence is defined as the absorption and re-emission of photons due to real electronic transitions, while Raman scattering is characterized as an inelastic scattering process resulting from virtual electronic-vibrational transitions. The conversation also touches on the concept of a photon "losing its identity" during these processes, particularly in the context of resonance Raman scattering, where no virtual states are involved.

PREREQUISITES
  • Understanding of fluorescence and its relation to electronic transitions
  • Knowledge of Raman scattering and its inelastic nature
  • Familiarity with resonance Raman scattering concepts
  • Basic principles of photon behavior in quantum mechanics
NEXT STEPS
  • Research the principles of fluorescence spectroscopy
  • Explore the mechanisms of Raman scattering in detail
  • Study the differences between resonance Raman scattering and traditional Raman scattering
  • Investigate the role of virtual states in quantum transitions
USEFUL FOR

Researchers in spectroscopy, physicists studying light-matter interactions, and chemists interested in molecular transitions will benefit from this discussion.

AlKindi
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If the fluorescence is the re-emitting of a photon with a larger wave length due to the transition from a higher energy state to a lower energy state in the case of resonance Raman (where there aren't any virtual states) seems be equal to the fluorescence. Which differences are there?
 
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Fluorescence occurs due to real electronic transitions, while Raman scattering occurs as a result of virtual electronic-vibrational transitions.

That is, fluorescence is an absorption/re-emission process while Raman scattering is an inelastic scattering process.

Claude.
 
Claude's answer brings up an interesting point about this problem: when does a photon "lose its identity" and become classified as a "re-emitted" photon?
 
Claude Bile said:
Fluorescence occurs due to real electronic transitions, while Raman scattering occurs as a result of virtual electronic-vibrational transitions.

That is, fluorescence is an absorption/re-emission process while Raman scattering is an inelastic scattering process.

Claude.

Thanks Claude, but what's about Resonace Raman scattering are there any virtual electronic states involve? I don't think so... [Modern Raman Spectroscopy– A Practical Approach p. 94]
 
fsonnichsen said:
Claude's answer brings up an interesting point about this problem: when does a photon "lose its identity" and become classified as a "re-emitted" photon?

I think when a photon (and the wave associeted) interact costructively with a system there is a time in which the photon "lose its identity" (e.g. the 10-5 seconds for the fluorescence) the energy is non more in the photon but in the system e.g. molecule. So we can say that it is re-emitted because of this transition I think we can also say the system (the molecule, the atoms etc. etc.) is re-formed.
 

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