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I apologise. It will take a while to come back with fully intelligent questions and answers. I've recently retired and hoped that I will finally have time to pursue some basic layman questions about the Equivalence Principle that arose during science books I read long ago, before the internet. There is also a bit of domestic pressure to tackle home projects that have accumulated over the years rather than spend time on the internet. I will have to be devious.
Lacking advanced formal education, I think I may be in over my head here for the time being. The first post was simple enough for me to understand in terms of geometry. But I don't have enough of an advanced education to quickly understand some of the math language and acronyms used as this thread proceeded, so there is a language barrier for me to overcome that will take more time.
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In reply to stevendaryl,
Apparently I may have been mistaken in my belief that the Equivalent Principle is fully equivalent. I took info such as
this rendition of Einsteins statement, and
subsequent development, quite literally.
I don't entirely understand what you meant by,
"But the two cases are different, if you perform precise measurements of g." Does that mean that the loss of apparent "weight" by Kirk will be present in both cases, but different, when the rocket is sitting on the ground as opposed to an inertial reaction in an accelerating rocket? What about the clock variation? Will time differences also be different when sitting on the ground as opposed to accelerating in the rocket? I am unable to see this.
Not knowing any better, regarding the Equivalence Principle not being equivalent, I think I worked out a simple relativity model where tidal forces are seemingly also included on the rocket because of Special Relativity, but have since found that that is a highly unusual perspective. It is easier to envision with a different, rather odd thought experiment. There is even a paragraph to this conventional
"tidal shortcoming" towards the end of the wiki
development section mentioned earlier.
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In reply to jartsa,
Yes, the bending of the light should occur in both cases, whether the elevator is sitting still on the ground or being drawn up by cable. I am delighted we see it the same. But again, would it be a varied curve difference between the two?
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In reply to 1977ub,
It is you I must apologise to most profusely for dragging your thread down to my level and slightly diverting it. Thank you for your tolerance.
I tend to regard foreshortening as a real phenomena that may even be easily observable in a very strange way. My thought was that regardless of motions throughout the endless universe, there is a theoretical average that is most at rest. Since the average rest might be any position and light must be at a relative constant speed to include all other observers, that is the philosophical reason any external observer (beholder) may regard themselves at rest.
To Kirk and Scotty, the rest of the universe is really foreshortening while they observe themselves to remain "uncompressed" in assumed current local time. They actually observe the external universe in an earlier, shorter condition. I know this may not make sense to you. It too, is hard for me to explain without a suitable visual descriptive thought experiment.
I do regard the speed of light as universal in a vacuum. Whereas "nothing may go faster than the speed of light in a vacuum", my thought is nothing
can be observed to go faster than the speed of light in a vacuum. Perhaps most importantly, light cannot go slower in a vacuum.
In my opinion, the time-dilation/reverse-time-dilation in an accelerating rocket can best be explained by considering that all indicators of time involve additional motion to create an event (tick-tock). Since a vibrating atom, a pendulum, a reciprocating flywheel and all other event-creating clocks must have their own inherent motion, the time mechanism must have additional motion
in addition to the forward motion of the spacecraft . But the closer to lightspeed the addition of motions become, the slower the periodic clock events must progress so they may theoretically gradually arrive at zero, the time-stop instant when all the total available "speed" is entirely used up by forward motion at "C", lightspeed. In the above case of Kirk vs Scotty at acceleration, one gentleman is traveling faster than the other, and their ever-slowing respective clock event motions cannot proceed at equal ticks until they both arrive at zero. I hope this makes sense.
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Wes